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rest-mass derived purely from Maxwell Equations summation of ridges
and troughs #1252 New Physics #1372 ATOM TOTALITY 5th ed
Posted:
Feb 23, 2013 2:00 AM
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What I am doing here with rest mass is not altogether new to physics
but a continuation and elaboration of what is found in this textbook:
In the textbook CHEM ONE by Waser, Trueblood, Knobler, 2nd ed., 1980,
page 307 is a picture of the
Debroglie waves for permitted and prohibited orbitals.
And so the idea I am pursuing is that the electron has that ring
shaped or closed loop shaped geometry and the ridges and troughs of E-
charge and M+ or M- magnetic monopoles when added up gives rest-mass.
So that a M+ ridge is a 1 eV rest mass and a E- ridge is another 1 eV
rest mass and the troughs are each 1 more eV rest mass and so the
electron in ground state sums up both ridges and troughs of E- and M+
(perhaps M-) sums to a total of
500,000 eV rest-mass. The same goes for the proton of its troughs and
ridges when summed equals 938,000,000 eV rest mass.
Now there are a lot of kinks and issues I have to overcome, but that
is to be expected. What I am concerned with is getting a general
framework for the 6th edition and if I have kinks and issues, I can
work them out in the 6th edition.
Now I wonder if the electron wavelength has ever been measured and how
many such ridges and troughs would exist in the hydrogen atom electron
in ground state. So if these parameters are available and if they come
up with say 400,000 or 500,000 or 600,000 such ridges and troughs, it
is safe to say I conclusively discovered the meaning of rest-mass.
And if the proton in hydrogen in ground state comes up with a number
for the ridges and troughs to be about 1,000,000,000 then there also I
conclusively discovered the inner meaning of rest mass.
I think the physics literature has some sort of numbers data of the
wavelength of the proton and electron and how many troughs and ridges
accrues from orbitals as shown in CHEM ONE.
Now earlier today I wrote that the proton is likely to involve a
volume of the wave but I rather doubt that, and suspect that the
proton wave is a surface area of a ellipsoid, not a volume of the
ellipsoid. So that the electron is circumference of C = pi(2r) and the
proton is surface area of S.A.= 4pi(r^2). I changed my mind because
the Maxwell Equations are about electricity which is a surface
phenomenon more than a solid interior phenomenon. And the fact that
10^9 is easier to come by from squaring 10^4 or 10^5.
Now probably the biggest kink in the armor of this, is likely to be
that I need to inject the plutonium atom rather than the hydrogen atom
ground state. So that the proton ellipsoid is going to be highly
elongated whereas the hydrogen is closer to spherical.
And keep in mind, the proton is the bar magnet in Faraday's law and
the electron is the closed loop wire, so that the electron Space of
its circle has to be far larger than the proton surface area that is
going to be a plunging bar magnet into the electron closed loop. Now
this maybe difficult to pull off since the electron has only 500,000
ridges and troughs to work with while the proton has 938,000,000
ridges and troughs to work with. I would be more comfortable if the
electron had 938,000,000 ridges and troughs to build a closed loop
wire.
Another kink is whether only M+ resides with electrons or whether both
M+ and M- reside.
So I have a lot of issues, but do not care so long as I have the
correct overall general framework. The fact that the chemistry text
has almost the identical idea, except they do not push it further
along into making rest mass, is supporting evidence that I am on the
correct framework.
--
Google's archives are top-heavy in hate-spew from search-engine-
bombing. Only Drexel's Math Forum has done a excellent, simple and
fair archiving of AP posts for the past 15 years as seen here:
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Archimedes Plutonium
http://www.iw.net/~a_plutonium
whole entire Universe is just one big atom
where dots of the electron-dot-cloud are galaxies
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