
Re: Alternative solution for NAN
Posted:
Feb 27, 2013 5:22 AM


"Torsten" wrote in message <kgklbh$6ph$1@newscl01ah.mathworks.com>... > "Carl S." wrote in message <kgki2g$rie$1@newscl01ah.mathworks.com>... > > The following code gives NAN (Not a Number) values > > [U,D]=eig(N); > > > > To solve this problem, I wrote that > > while(det(N) == 0) > > N=(1e10.*randi(1,size(N)))*eye(size(N)); > > end > > > > But, the loop does not stop > > Your matrix N within the loop always has determinant (1e10)^(size(N)) > which may become very small if N is large. > > :( Are there any alternative solution instead of this loop to solve the NAN problem ? > > Depends on the original matrix N. > > Best wishes > Torsten.
Dear Torsten, The matrix N has standard deviation values of grayscale images. So, it changes for each image. How to solve the NAN problem in this case ?

