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Torsten
Posts:
1,440
Registered:
11/8/10


Re: Finding an easy substitution for a complicated function
Posted:
Mar 6, 2013 4:11 AM


"Asma" wrote in message <kh6uu9$jgm$1@newscl01ah.mathworks.com>... > Hi, > > I have a very tedious function (including arctan, arcsin, sqrt etc) having a number of controlling parameters. > When I plot this function, I get a simple exponential looking curve. > > I want to approximate my function with a nonlinear function possibly an exponential exp(lambda*x), a sum of exponentials or any simple function. But I want this approximation to incorporate all parameters (i.e. lambda should be a function of all controlling parameters). > > Kindly tell me how can I substitute a complicated function with a simple function through Matlab.
So you want to get complicated response from a simple function type ? In general this won't be possible.
Best wishes Torsten.



