D R G <email@example.com> wrote in message <firstname.lastname@example.org>... > Yes, that is what I want to solve; however, the case you're referring to is I believe the trivial case; we have already solved for when k = 0, and got a non-trivial solution. As K is small, this will be close to it and there will be non zero solutions. > > Regards > > DRG >
No, y=0 is the only solution that satisfies your differential equation together with the two boundary conditions - also for the case K and/or J not equal to 0. You will have to change the boundary conditions to get a solution different from y=0.