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Re: Intersection points of two contour plots
Posted:
May 1, 2013 9:40 PM
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ContourPlot[Sin[3 x*y] == 0, {x, -3, 3}, {y, -3, 3}, RegionFunction -> Function[{x, y}, x*y < 0], Exclusions -> {x*y == 0}, ContourStyle -> Black]
or
t1 = Table[ If[x*y < 0, Sin[3 x*y], Sequence[]], {x, -3, 3, .1}, {y, -3, 3, .1}];
ListContourPlot[t1, Contours -> {0}, ContourShading -> False, DataRange -> {{-3, 3}, {-3, 3}}, RegionFunction -> Function[{x, y}, x*y < 0], ContourStyle -> Black]
Bob Hanlon
On Wed, May 1, 2013 at 3:36 AM, Luiz Melo <lmelo@ufsj.edu.br> wrote:
> Hi group, > Please consider the example below to illustrate my question (the > original problem is somehow much more complicated): > > t1 = Table[Sin[3 x*y], {x, -3, 3, .1}, {y, -3, 3, .1}]; > > t2 = Table[If[x*y < 0, Sin[3 x*y]], {x, -3, 3, .1}, {y, -3, 3, .1}]; > > p1 = ListContourPlot[t1, Contours -> {0}, ContourShading -> False, > DataRange -> {{-3, 3}, {-3, 3}}, ContourStyle -> Black]; > > p2 = ListContourPlot[t2, Contours -> {0}, ContourShading -> False, > DataRange -> {{-3, 3}, {-3, 3}}, ContourStyle -> {Red, Dashed, Thick}]; > > Show[p1, p2] > > Is there a way to show only the results of the intersection of these > two contour plots? > > Thank you > Luiz > >
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