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Re: An analytical solution to an integral not currently
Posted:
Jul 16, 2013 5:55 AM


Hola:
Input: (Sqrt(Log[x])^1 + a*x + b)
Result:
Integrate[Sqrt[Log[x]]^(1) + a*x + b, x] = (x*(2*b + a*x + 4*DawsonF[Sqrt[Log[x]]]))/2
From:
http://integrals.wolfram.com/index.jsp?expr=%28Sqrt%28Log[x]%29^1+%2B+a*x+%2B+b%29&random=false
Muchos saludos,
MATTHIAS BODE LVSABA@HOTMAIL.COM
> From: rprogrammer@gmail.com > Subject: An analytical solution to an integral not currently in Mathematica? > To: mathgroup@smc.vnet.net > Date: Sun, 14 Jul 2013 01:48:46 0400 > > Question: Integral dx of 1/sqrt(Log[x] + a*x + b) > (sorry if my notation is off; I just used the online integrator and don't have Mathematica proper, http://integrals.wolfram.com/index.jsp?expr=1%2Fsqrt%28Log%5Bx%5D+%2B+a*x+%2B+b%29) > (the online integrator returned this as of the time of writing this (20130713): "Mathematica could not find a formula for your integral. Most likely this means that no formula exists." ) > > > Another system's unconfirmed answer (in that notation; sorry) (version 5.27.0): sqrt(%pi)*%i*%e^(a*xb)*erf(%i*sqrt(log(x)+a*x+b)) > > Strangely, the other system only produces this result when given, say, x(t) in all places for x (including variable of integration). > > I can't seem to get the other system to verify its result symbolically, but when I try random numerical sampling, it does seem to agree, albeit horribly plagued by floating point errors for large x. > > > Can anyone offer insight, or possibly prove it's correctness or incorrectness? :) > > > (P.S. I just joined this group, so apologies if it's the wrong one or I'm not following guidelines) >



