
Re: parametric plot and filling
Posted:
Aug 22, 2013 12:47 AM


I also noticed that Solve does not need the Thread. This also works:
Plot[Evaluate[y /. { Solve[{x, y} == {2 t, t^2}, {y, t}], Solve[{x, y} == {6 + 2 t, t^2}, {y, t}]}], {x, 4, 10}, Axes > {True, False}, Ticks > None, PlotStyle > {{Thick, Cyan}, {Thick, Green}}, PlotRange > {4, 0}, AspectRatio > 0.285714, Filling > 4]
Bob Hanlon
On Wed, Aug 21, 2013 at 1:58 AM, Bob Hanlon <hanlonr357@gmail.com> wrote:
> > I would try to convert it to a standard plot. > > > ParametricPlot[ > {{2 t, t^2}, {6 + 2 t, t^2}}, > {t, 2, 2}, > Axes > {True, False}, > Ticks > None, > PlotStyle > {{Thick, Cyan}, {Thick, Green}}] > > > Plot[ > Evaluate[y /. { > Solve[Thread[ > {x, y} == {2 t, t^2}], {y, t}], > Solve[Thread[ > {x, y} == {6 + 2 t, t^2}], {y, t}]}], > {x, 4, 10}, > Axes > {True, False}, > Ticks > None, > PlotStyle > {{Thick, Cyan}, {Thick, Green}}, > PlotRange > {4, 0}, > AspectRatio > 0.285714, > Filling > 4] > > > > Bob Hanlon > > > > > On Tue, Aug 20, 2013 at 7:36 AM, Francisco Gutierrez < > fgutiers2002@yahoo.com > > wrote: > > > > > Dear group: > > > > DoesParametricPlot admit the Filling option? Seems it not? How then to > > perform it? > > Lokk at the following simple example: > > > > ParametricPlot[{{2 t,t^2},{6+ 2 t,t^2}}, {t,2,2},Axes>{True,False}, > > Ticks>None, PlotStyle>{{Thick,Cyan},{Thick,Green}}] > > > > > > > > The if I introduce the Filling command inside PlotStyle nothing happens, > > and outside it produces an error. Any ideas? > > francisco > > > > >

