
Re: Order embedding
Posted:
Sep 16, 2013 3:33 PM


In message <o19e391hgcgk4fv7bd126p7lsle5g9j89o@4ax.com>, dullrich@sprynet.com writes >>> f:X > Y is an order embedding when >>> for all x,y, (x <= y iff f(x) <= f(y)). >> >>Yes. > >I think no. Surely an embedding is required to be injective.
f(x) = f(y) => f(x) <= f(y) and f(y) <= f(x) => x <= y and y <= x => x = y
 David Hartley

