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Topic:
Find the perfect square closest to n(x), i just want the perfect square above or below no decimals. Can it be solved using geometry?
Replies:
7
Last Post:
Nov 1, 2013 8:53 PM



JT
Posts:
1,448
Registered:
4/7/12


Re: Find the perfect square closest to n(x), i just want the perfect square above or below no decimals. Can it be solved using geometry?
Posted:
Nov 1, 2013 10:03 AM


Den fredagen den 1:e november 2013 kl. 04:01:53 UTC+1 skrev Ben Bacarisse: > jonas.thornvall@gmail.com writes: > > <snip> > > > Actually Ben i have a similar that may be easier for you to follow, > > > any square can be divided into 4 sub squares. And if we have a number > > > we can find the 10^x above it and 10^x1 below it. >
> > > So 10^x is 1 now we can chose if we want 0 at real zero or zero at > > > square 10^x1 If we choose the later we close in faster. Now the area > > > between the lesser and bigger square or if we use zero, can be > > > described as a percentage ratio of the height. > > > Sorry, I can't make head nor tail of this. > I find it hard to beleive that a skille mathematician can not understand this principle. HERE ENDS BIG SQUARE BETWEEN SMALL BIG IS RANGE Sqrt=Height=number*1,0 (10*10)/100=1.0 of area Sqrt=Height=number*0,9 (9*9)/100=0.81 of area Sqrt=Height=number*0,8 (8*8)/100=0.64 ... Sqrt=Height=number*0,7 (7*7)/100=0.49 ... Sqrt=Height=number*0,6 (6*6)/100=0.36 ... Sqrt=Height=number*0,5 (5*5)/100=0.25 ... Sqrt=Height=number*0,4 (4*4)/100=0.16 ... Sqrt=Height=number*0,3 (3*3)/100=0.09 ... Sqrt=Height=number*0,2 (2*2)/100=0.04 ... Sqrt=Height=number*0,1 (1*1)/100=0.01 ... HERE START SMALL SQUARE BETWEEN SMALL AND BIG IS RANGE > > <snip> > > > The perfect square we find is subtracted from our number and now we > > > work same approach for this smaller square. This is repeated until the > > > full number is encoded to a series of squares + a small integer less > > > then 4. > > > > Yes, this bit I've understood, but why? What's the point of doing this? > > > > <snip> > >  > > Ben.



