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Topic: Formal proof of the ambiguity of 0^0
Replies: 6   Last Post: Nov 17, 2013 2:04 PM

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Dan Christensen

Posts: 8,219
Registered: 7/9/08
Re: Formal proof of the ambiguity of 0^0
Posted: Nov 17, 2013 1:38 PM
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On Sunday, November 17, 2013 12:14:04 PM UTC-5, Julio Di Egidio wrote:
> "Dan Christensen" <> wrote in message

> > On Sunday, November 17, 2013 10:19:33 AM UTC-5, Julio Di Egidio wrote:
> <snip>

> >> We were simply explained that 0^0 = 0/0, because x^0 = x/x when extending
> >> the notion of repeated multiplication to non-positive exponents.
> >
> > I can see the reasoning behind it, but I don't like the idea setting two
> > undefined expressions equal to one another.
> Nobody is setting two undefined expressions *equal* to one another, I was
> speaking informally.


> Regardless, you quote elementary algebra books, so not
> addressing objections.

I don't need elementary algebra books to justify my position. We were discussing what is taught in high schools. I don't under your other objections. I was not talking about extending any functions.

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