
Re: Formal proof of the ambiguity of 0^0
Posted:
Nov 17, 2013 1:38 PM


On Sunday, November 17, 2013 12:14:04 PM UTC5, Julio Di Egidio wrote: > "Dan Christensen" <Dan_Christensen@sympatico.ca> wrote in message > > news:05b0baba558f4c1980f2f627dbd1b441@googlegroups.com... > > > On Sunday, November 17, 2013 10:19:33 AM UTC5, Julio Di Egidio wrote: > > <snip> > > >> We were simply explained that 0^0 = 0/0, because x^0 = x/x when extending > > >> the notion of repeated multiplication to nonpositive exponents. > > > > > > I can see the reasoning behind it, but I don't like the idea setting two > > > undefined expressions equal to one another. > > > > Nobody is setting two undefined expressions *equal* to one another, I was > > speaking informally.
OK.
> Regardless, you quote elementary algebra books, so not > > addressing objections. >
I don't need elementary algebra books to justify my position. We were discussing what is taught in high schools. I don't under your other objections. I was not talking about extending any functions.
Dan Download my DC Proof 2.0 software at http://www.dcproof.com Visit my new math blog at http://www.dcproof.wordpress.com

