
Re: Removing singularity at x=0 for integral
Posted:
Nov 27, 2013 6:13 PM


On Tuesday, November 26, 2013 10:10:58 PM UTC5, robin....@gmail.com wrote: > On Wednesday, November 27, 2013 2:10:25 AM UTC+11, dsp...@netscape.net wrote: >
> > > It doesn't matter whether the exponential goes to zero faster than the power. > > The fact is that you can't divide by zero in both the exponential and the power. >
By the exponential going to zero faster than the power > the limit does exist, and you should be able to remove the singularity.
In fact  I found that I can that by splitting x^0.5 = x^0.5 * x^2. Then use integration by parts. Letting dv = 1/x^2 * exp(A/x) then you can easily integrate to find v.
Thanks for the help. David

