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Topic: Re: Matheology sqrt(-2): WM admits to unlistability of 0/1 sequences
Replies: 4   Last Post: Dec 22, 2013 8:00 PM

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JT

Posts: 1,148
Registered: 4/7/12
Re: Matheology sqrt(-2): WM admits to unlistability of 0/1 sequences
Posted: Dec 21, 2013 9:40 PM
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Den söndagen den 22:e december 2013 kl. 02:51:14 UTC+1 skrev jonas.t...@gmail.com:
> Den söndagen den 22:e december 2013 kl. 02:25:35 UTC+1 skrev jonas.t...@gmail.com:
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> > Den lördagen den 21:e december 2013 kl. 23:32:57 UTC+1 skrev wpih...@gmail.com:
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> > > On Saturday, December 21, 2013 6:22:05 PM UTC-4, jonas.t...@gmail.com wrote:
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> > > > You see it is all very simple to be able to claim that 0.999... actually add up to 1. You must be able to prove that there is such x that 10^-x actually equals zero and i do not see how you can.
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> > > You can't because it is never true. Fortunately, you dont't have to. 0.111... is equal to 1. (Hint look at the *limit* of the partial sums. Or look up the definition of infinite sum in a first year Calculus book. It has nothing to do with your imbecilic twaddle about adding up an infinite number of integers.)
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> > > William Hughes
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> > Oh fuck and i who always thought that 0.111... added up to 1/9 i must have missed something very fundamental. Or you have had a total mental breakdown i don't know...
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> Or 1/9 can not be represented correctly in decimal base. But it works perfectly well in base 9.
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> Simply 0.1 or 0.09


Well since this base nine notation is bijective and should be without zeros it may be better writing it out .1 or .[1]9 so 1 equals .9 actually it also equals .89 and .889 and so on using bijective notation

So .888... would not equal 1 in nonary bijective systems although you could add a 9 after any numbers of .88888888889 to make it 1.

But they do all used finished decimal expansion.



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