In article <firstname.lastname@example.org>, <email@example.com> wrote:
> Compute the integral from 0 to 1 of ln(1+x)/(1+x^2)dx. Hint: Use the > substitution y+1=2/(x+1)
Just to be sure: do you mean
ln(1+x) ------- 1+x^2
ln( (1+x)/(1+x^2) )?
The first one does not seem to evaluate to closed form, the second one is standard: write as ln(1+x) - ln(1+x^2) and do them by parts, using the trick int(f) = x*f - int(x*f'). Works here since the f' terms have no "ln" in them and in both case x*f' is trivial to integrate.