Date: Jan 22, 2009 3:54 AM
Author: Henry
Subject: Re: -1 x -1 ?
On 22 Jan, 01:51, Tay <wintct...@gmail.com> wrote:

> -1 *-1 = 1 huh?

> The minus (negative) signs cancel eachother out:

> (-1)(-1) = [(-)(-)](1x1) = (+)(1x1) = +1

> It's so simple.

How do you know the two negative signs cancel each other out in

multiplication?

With (-x) being the additive inverse of x in a [unitary] ring,

I would allow you (-(-x)) = x, i.e. (-x)+x = 0 and x+(-x) = 0.

You can also have 1*x = x, x*1 = x, x*0 = 0 and 0*x = 0.

Consider (-1)*1 + (-1)*(-1) = (-1) * (1+(-1)) = (-1) * 0 = 0.

But (-1)*1 = (-1).

So (-1) + (-1)*(-1) = 0 and so (-1)*(-1) = 1.