Date: Nov 15, 2012 5:28 AM
Author: William Elliot
Subject: Re: Curvature in Cartesian Plane
On Thu, 15 Nov 2012, Brad Cooper wrote:

> "Mike Terry" <news.dead.person.stones@darjeeling.plus.com> wrote in message

> While investigating this I came across this in Spiegel's Vector Analysis:

>

> The radius of curvature rho of a plane curve with equation y = f(x),

> i.e. a curve in the xy plane is given by

>

> rho = sqrt(1+(y')^2) / |y''|

>

No, rho = (1 + y'^2)^(3/2) / |y"|

> I tested this with the simple hemisphere y = sqrt(1-x^2).

That's a semicircle.