Date: Nov 15, 2012 5:28 AM
Author: William Elliot
Subject: Re: Curvature in Cartesian Plane
On Thu, 15 Nov 2012, Brad Cooper wrote:
> "Mike Terry" <firstname.lastname@example.org> wrote in message
> While investigating this I came across this in Spiegel's Vector Analysis:
> The radius of curvature rho of a plane curve with equation y = f(x),
> i.e. a curve in the xy plane is given by
> rho = sqrt(1+(y')^2) / |y''|
No, rho = (1 + y'^2)^(3/2) / |y"|
> I tested this with the simple hemisphere y = sqrt(1-x^2).
That's a semicircle.