```Date: Jan 30, 2013 10:05 PM
Author: Chris Arthur
Subject: Re: List manipulation question - 2013

Lea,You might try something likeMap[Position[list1,#]&,list2]this will give you a list of how the two lists coincide.  It means, for each element in list2, find its position in list1, and give me a list of the positions.ChrisLea Rebanks a écrit :> Dear All,>> I have the follow problem with the combination of a few lists.> I shall outline the problem or what I am trying to do.> I know that to solve this problem requires a number of processes, but I am> not sure how to setup the coding to achieve my desired result.> Please could someone show me the coding for this problem.>> The problem:-> 1 - I have a list1 created from 24+(15*n1)        All n1 are integers> 1,2,3,4.....to a large number of integers.> 2 - I want to divide the list1 by 24 and create another list2 with only the> integer results in list2.>      Table[24 + 15*i, {i, 100}]/24  ...    so that integer results in list2> = { 144, 264, 384, 504, 624, 744, 864, 984, 1104 }> 3 - I have another list3 created from 12+(3*n2)   All n2 are integers> 1,2,3,4.....to a large number of integers.> 4 - With list3 I want to find  :->      (i) The integer number of n2 that either equates 12+(3*n2) = 144 or> the next FIRST available number in list2 that meets this equality.>  then also    (ii)The integer number(s) of n2 that equates 12+(3*n2) = 24+(15*n1) after the first equal value for say 6 repetitions.>  then also     (iii)The integer number(s) of n1 that equates 12+(3*n2) => 24+(15*n1) after the first equal value for say 6 repetitions.>> The above example is quite simple, but I am hoping to setup the coding to> work with other integer values instead of 3 & 15 which will present more of> a challenge.>> Any help or advice greatly appreciated.> Best regards,> Lea...>>>>
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