```Date: Jan 30, 2013 10:05 PM
Author: Bob Hanlon
Subject: Re: List manipulation question - 2013

list1 = Table[24 + (15*n1), {n1, 2000}];Take[Select[list1/24, IntegerQ], 9]{6, 11, 16, 21, 26, 31, 36, 41, 46}Take[Select[list1, IntegerQ[#/24] &], 9]{144, 264, 384, 504, 624, 744, 864, 984, 1104}Apparently you want list2 to consist of the members of list1 that areinteger multiples of 24 rather than the integers in list1/24.list2 = Select[list1, IntegerQ[#/24] &];list3 = n2 /. Solve[       {12 + (3*n2) == #, Element[n2, Integers]},       n2][[1]] & /@ list2;Length[list2] == Length[list3]TrueBob HanlonConsequently, there is an integer n2 for every element of list2.On Wed, Jan 30, 2013 at 4:26 AM, Lea Rebanks <lrebanks@gmail.com> wrote:>> Dear All,>> I have the follow problem with the combination of a few lists.> I shall outline the problem or what I am trying to do.> I know that to solve this problem requires a number of processes, but I am> not sure how to setup the coding to achieve my desired result.> Please could someone show me the coding for this problem.>> The problem:-> 1 - I have a list1 created from 24+(15*n1)        All n1 are integers> 1,2,3,4.....to a large number of integers.> 2 - I want to divide the list1 by 24 and create another list2 with only the> integer results in list2.>      Table[24 + 15*i, {i, 100}]/24  ...    so that integer results in list2> = { 144, 264, 384, 504, 624, 744, 864, 984, 1104 }> 3 - I have another list3 created from 12+(3*n2)   All n2 are integers> 1,2,3,4.....to a large number of integers.> 4 - With list3 I want to find  :->      (i) The integer number of n2 that either equates 12+(3*n2) = 144 or> the next FIRST available number in list2 that meets this equality.>  then also    (ii)The integer number(s) of n2 that equates 12+(3*n2) = 24+(15*n1) after the first equal value for say 6 repetitions.>  then also     (iii)The integer number(s) of n1 that equates 12+(3*n2) => 24+(15*n1) after the first equal value for say 6 repetitions.>> The above example is quite simple, but I am hoping to setup the coding to> work with other integer values instead of 3 & 15 which will present more of> a challenge.>> Any help or advice greatly appreciated.> Best regards,> Lea...>>
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