```Date: Jan 31, 2013 3:05 AM
Author: Tom Potter
Subject: Re: The 11 Most Beautiful Mathematical Equations

"1treePetrifiedForestLane" <Space998@hotmail.com> wrote in message news:8be240f8-71b6-4b00-9911-790f5fd85137@rm7g2000pbc.googlegroups.com...what is your take on Malus' law, what ever it issupposed to be, viz Ohm's?...  I didn't bother, becauseanyone who is really into electronics, enough,uses complex impedances (or what ever).>  V = i * (I" cos^2(A)) = I * R> ( Modification of Ohm's Law taking Malus's law into account to model> conductivity. )>> And where is hanson's equation that models oscillators in a gravity field?> but note that hanson's equation is simplier andhanson's equation accounts for the 38 microseconds per dayoffset between a clock at sea level and one in a GPS orbit.Search Google Groups for "m_e/h * 2G/c^2 * 86400" for details.If you want to know how Malus's law models impedanceread Plutonium's posts.Here is another beautiful equation the writer missed.*****   events = Q * k * R / T   ******According to Shannon:information entropy = 1 / ln(2) bits.( Which in itself is a Beautiful Mathematical Equation.)http://en.wikipedia.org/wiki/Bithttp://www.ueltschi.org/teaching/chapShannon.pdfhttp://code.activestate.com/recipes/577476-shannon-entropy-calculation/According to thermodynamics:physical entropy  = 1.3806488(13)×10?23 joules per degree K(Boltzmann constant)http://en.wikipedia.org/wiki/Boltzmann_constantSo about 1 x 10^23 bits equals one joule per degree K.According to Potter's 7th law,one elemental quantum event = one bit = one cycle,and there are about 10^23 quantum events per joule per degree K.One joule is equal to the energy expended (or work done)in passing an electric current of one amperethrough a resistance of one ohmfor one second.( Power = current^2 * resistance )( Energy = power * time )One ampere is one coulomb of electrons per second,and there are 6.2415 × 10^18 electrons in a coulombso the passage of 6.2415 × 10^18 electronsthrough a resistance of one ohm involves10^23 quantum events per degree K.thus it requires about 15,000 quantum eventsfor one electron to traverse a one ohm resistorfor each degree K.Thus at a constant temperature,resistance can be equated to the numberquantum events (Cycles) required to get electrons through the traffic jam.quantum events = electrons * potter's constant ( About 15,000) * resistance/ degrees K.Next time I am in Vienna,I think I'll spray paint it on Boltzmann's tomb stone.events  = Q * k * R / T-- Tom Potterhttp://tom-potter.telhttps://tdp1001.jux.comhttp://warp-to.ushttp://the-cloud-machine.tk
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