Date: Jan 31, 2013 3:05 AM Author: Tom Potter Subject: Re: The 11 Most Beautiful Mathematical Equations

"1treePetrifiedForestLane" <Space998@hotmail.com> wrote in message

news:8be240f8-71b6-4b00-9911-790f5fd85137@rm7g2000pbc.googlegroups.com...

what is your take on Malus' law, what ever it is

supposed to be, viz Ohm's?... I didn't bother, because

anyone who is really into electronics, enough,

uses complex impedances (or what ever).

> V = i * (I" cos^2(A)) = I * R

> ( Modification of Ohm's Law taking Malus's law into account to model

> conductivity. )

>

> And where is hanson's equation that models oscillators in a gravity field?

> but note that hanson's equation is simplier and

hanson's equation accounts for the 38 microseconds per day

offset between a clock at sea level and one in a GPS orbit.

Search Google Groups for "m_e/h * 2G/c^2 * 86400" for details.

If you want to know how Malus's law models impedance

read Plutonium's posts.

Here is another beautiful equation the writer missed.

***** events = Q * k * R / T ******

According to Shannon:

information entropy = 1 / ln(2) bits.

( Which in itself is a Beautiful Mathematical Equation.)

http://en.wikipedia.org/wiki/Bit

http://www.ueltschi.org/teaching/chapShannon.pdf

http://code.activestate.com/recipes/577476-shannon-entropy-calculation/

According to thermodynamics:

physical entropy = 1.3806488(13)×10?23 joules per degree K

(Boltzmann constant)

http://en.wikipedia.org/wiki/Boltzmann_constant

So about 1 x 10^23 bits equals one joule per degree K.

According to Potter's 7th law,

one elemental quantum event = one bit = one cycle,

and there are about 10^23 quantum events per joule per degree K.

One joule is equal to the energy expended (or work done)

in passing an electric current of one ampere

through a resistance of one ohm

for one second.

( Power = current^2 * resistance )

( Energy = power * time )

One ampere is one coulomb of electrons per second,

and there are 6.2415 × 10^18 electrons in a coulomb

so the passage of 6.2415 × 10^18 electrons

through a resistance of one ohm involves

10^23 quantum events per degree K.

thus it requires about 15,000 quantum events

for one electron to traverse a one ohm resistor

for each degree K.

Thus at a constant temperature,

resistance can be equated to the number

quantum events (Cycles) required to get electrons through the traffic jam.

quantum events = electrons * potter's constant ( About 15,000) * resistance

/ degrees K.

Next time I am in Vienna,

I think I'll spray paint it on Boltzmann's tomb stone.

events = Q * k * R / T

--

Tom Potter

http://tom-potter.tel

https://tdp1001.jux.com

http://warp-to.us

http://the-cloud-machine.tk