```Date: Mar 14, 2013 3:39 AM
Author: William Hughes
Subject: Re: Matheology § 222 Back to the roots

On Mar 13, 11:05 pm, WM <mueck...@rz.fh-augsburg.de> wrote:> On 13 Mrz., 22:41, William Hughes <wpihug...@gmail.com> wrote:>> > Let J be a set of the lines of L with no> > findable last line.  At least two lines> > belong to J.  Are any lines of J necessary?>> Remove all lines.> Can any numbers remain in the list? No.> Therefore at least one line must remain in the list.>> We do not know which it is, but it is more than no line.> In other words, it is necessary, that one line remains.However, it is not necessary that any one particularline remain.  So while it is necessary that the setJ contain one line, there is no particular line l that isnecessary.<snip>> From the construction we know, that all numbers, that are in two> lines, are in one line.True.  And indeed all numbers are in two lines. However,not the same two lines.> Therefore your claim, that more than two lines> must remain in the list, is contradicted.False.  This would only follow if all numbers were inthe same two lines.
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