Date: Mar 14, 2013 3:39 AM
Author: William Hughes
Subject: Re: Matheology § 222 Back to the roots
On Mar 13, 11:05 pm, WM <mueck...@rz.fh-augsburg.de> wrote:

> On 13 Mrz., 22:41, William Hughes <wpihug...@gmail.com> wrote:

>

> > Let J be a set of the lines of L with no

> > findable last line. At least two lines

> > belong to J. Are any lines of J necessary?

>

> Remove all lines.

> Can any numbers remain in the list? No.

> Therefore at least one line must remain in the list.

>

> We do not know which it is, but it is more than no line.

> In other words, it is necessary, that one line remains.

However, it is not necessary that any one particular

line remain. So while it is necessary that the set

J contain one line, there is no particular line l that is

necessary.

<snip>

> From the construction we know, that all numbers, that are in two

> lines, are in one line.

True. And indeed all numbers are in two lines. However,

not the same two lines.

> Therefore your claim, that more than two lines

> must remain in the list, is contradicted.

False. This would only follow if all numbers were in

the same two lines.