Date: Mar 30, 2013 10:22 AM
Author: Jose Carlos Santos
Subject: Re: Integral calculation!

On 30-03-2013 10:11, Roland Franzius wrote:

>> I need to calculate integral(0,pi/4) x.tan x dx.
>>
>> http://at.yorku.ca/cgi-bin/bbqa?forum=calculus;task=list

>
> int dx x tan x = x^2 tan x - int dx x^2/(1+x^2)=


Wrong!

> x^2 tan x - int dx ( 1 - 1/(1+x^2) )


Best regards,

Jose Carlos Santos