Date: Oct 17, 2013 1:37 PM
Author: Bart Goddard
Subject: Re: Formal proof of the ambiguity of 0^0
Dan Christensen <Dan_Christensen@sympatico.ca> wrote in
> It works because you will still have the same values at every other
No, it doesn't have the same values at every other point.
("Point"? Really?) For instance, if you define 0^0=3,
3^2 = (0^0)^2 = 0^(2*0) = 0^0 = 3
and, for the fourth time, 9 does not equal 3, at least here
in the sane world.