Date: Oct 17, 2013 1:37 PM
Author: Bart Goddard
Subject: Re: Formal proof of the ambiguity of 0^0
Dan Christensen <Dan_Christensen@sympatico.ca> wrote in

news:558531f1-602a-4393-8320-058f4c011303@googlegroups.com:

> It works because you will still have the same values at every other

> point.

No, it doesn't have the same values at every other point.

("Point"? Really?) For instance, if you define 0^0=3,

then:

3^2 = (0^0)^2 = 0^(2*0) = 0^0 = 3

and, for the fourth time, 9 does not equal 3, at least here

in the sane world.