Date: Dec 4, 2013 1:28 PM Author: RGVickson@shaw.ca Subject: Re: Help me understand...INT (sin^5 x) On Wednesday, December 4, 2013 4:36:20 AM UTC-8, muhah...@hotmail.com wrote:

> Can you solve please (; dx/(cosx)5

If you mean to integrate cos(x)^5, the answer is

(1/5)sin(x)*cos(x)^4 +(4/15)sin(x)*cos(x)^2 + (8/15)sin(x) + C.

If you mean to integrate 1/cos(x)^5 the answer is

(1/4)sin(x)/cos(x)^4 + (3/8)sin(x)/cos(x)^2 + (3/8)ln[sec(x)+tan(x)] + C