http://mathforum.org/kb List of forum topics en http://mathforum.org/kb/thread.jspa?messageID=7905895&tstart=0#7905895 Oct 14, 2012 12:20:34 PM Oct 14, 2012 12:20:34 PM LaC0saNostra 0 http://mathforum.org/kb/thread.jspa?messageID=7905893&tstart=0#7905893 Oct 14, 2012 12:20:29 PM Oct 14, 2012 12:20:29 PM LaC0saNostra 1 http://mathforum.org/kb/thread.jspa?messageID=7905891&tstart=0#7905891 Oct 14, 2012 12:20:24 PM Oct 14, 2012 12:20:24 PM LaC0saNostra 0 http://mathforum.org/kb/thread.jspa?messageID=7905678&tstart=0#7905678
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Esther Brink wrote:
> Edward,
>]]> Oct 14, 2012 2:58:35 AM Oct 14, 2012 2:58:35 AM jawbrey@att.net 0 http://mathforum.org/kb/thread.jspa?messageID=7905580&tstart=0#7905580 Edward,
For (c), easiest choice is the identity function. For (a), one of the easiest choices is the doubling function, f(x) = 2x. For]]> Oct 13, 2012 10:09:54 PM Oct 13, 2012 10:09:54 PM benb 3 http://mathforum.org/kb/thread.jspa?messageID=7905179&tstart=0#7905179
injective: f(n) does not have two different n giving the same value
bijective:]]> Oct 13, 2012 2:45:30 AM Oct 13, 2012 2:45:30 AM hp1702 1 http://mathforum.org/kb/thread.jspa?messageID=7904635&tstart=0#7904635 (a.) injective but not surjective
(b.) surjective
(c.) and both]]> Oct 12, 2012 12:30:11 AM Oct 12, 2012 12:30:11 AM LaC0saNostra 6