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I thought I'd found a way round congruency conditions by giving each p_n the freedom to]]> Nov 15, 2012 2:52:12 PM Nov 15, 2012 2:52:12 PM manontheclaphamomnibus 0 http://mathforum.org/kb/thread.jspa?messageID=7923534&tstart=0#7923534 > Thanks for looking at it, trj.
>
> I need to think about your point - initially not sure
> I get your]]> Nov 15, 2012 8:04:03 AM Nov 15, 2012 8:04:03 AM trj 1 http://mathforum.org/kb/thread.jspa?messageID=7923327&tstart=0#7923327
I need to think about your point - initially not sure I get your point properly, so I might be confused.]]> Nov 14, 2012 8:29:34 PM Nov 14, 2012 8:29:34 PM manontheclaphamomnibus 2 http://mathforum.org/kb/thread.jspa?messageID=7923316&tstart=0#7923316 > argument
>
>
> To search for numbers n such that n-1 and n+1 are
> both prime, an initially]]> Nov 14, 2012 6:56:30 PM Nov 14, 2012 6:56:30 PM trj 3 http://mathforum.org/kb/thread.jspa?messageID=7923106&tstart=0#7923106
expression (2) should read

(2) number of valid n in that range = integer value of
1/2 (1/3 . 3/5 .... ((p_n-1) - 2)/(p_n-1) .]]> Nov 14, 2012 9:22:44 AM Nov 14, 2012 9:22:44 AM manontheclaphamomnibus 0 http://mathforum.org/kb/thread.jspa?messageID=7923101&tstart=0#7923101

To search for numbers n such that n-1 and n+1 are both prime, an initially appealing naive approach suggests n is chosen so that]]> Nov 14, 2012 9:18:40 AM Nov 14, 2012 9:18:40 AM manontheclaphamomnibus 5 http://mathforum.org/kb/thread.jspa?messageID=7922902&tstart=0#7922902 ]]> Nov 13, 2012 10:52:02 PM Nov 13, 2012 10:52:02 PM manontheclaphamomnibus 0 http://mathforum.org/kb/thread.jspa?messageID=7922875&tstart=0#7922875 > Can anyone help if I post a short argument with flaws
> in it?

Yes, usually.
]]> Nov 13, 2012 10:14:40 PM Nov 13, 2012 10:14:40 PM trj 7 http://mathforum.org/kb/thread.jspa?messageID=7922870&tstart=0#7922870 ]]> Nov 13, 2012 9:58:13 PM Nov 13, 2012 9:58:13 PM manontheclaphamomnibus 8