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        <item>
            <title>Re: Archimedes square root of 3</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=8250500&amp;tstart=0#8250500</link>

        

            <description><![CDATA[typos again ... fixed ...<br><br>E.J. Dijkerhuis "Archimedes" (1987) page 435 discussed<br><br>(27^1/2)/3 in terms of a continuing fraction]]></description>

        

            <jf:creationDate>Feb 5, 2013 9:23:41 AM</jf:creationDate>
            <jf:modificationDate>Feb 5, 2013 9:23:41 AM</jf:modificationDate>
            <jf:author>milogardner@juno.com</jf:author>
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        <item>
            <title>Re: Archimedes square root of 3</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=8248668&amp;tstart=0#8248668</link>

        

            <description><![CDATA[corrected by:<br><br>E.J. Dijkerhuis "Archimedes" (1987) page 435 discussed<br><br>(27^1/2)/3 in terms of a continuing fraction series<br><br>cited]]></description>

        

            <jf:creationDate>Feb 4, 2013 6:29:41 PM</jf:creationDate>
            <jf:modificationDate>Feb 4, 2013 6:29:41 PM</jf:modificationDate>
            <jf:author>milogardner@juno.com</jf:author>
            <jf:replyCount>1</jf:replyCount>
        </item>

        <item>
            <title>Re: Archimedes square root of 3</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=8248500&amp;tstart=0#8248500</link>

        

            <description><![CDATA[Reply<br><br>E.J. Dijkerhuis "Archimedes" page 435 discussed<br><br>(27^1/2)/3 in terms of a continuing fraction series<br><br>cited 3^1/2, 26/15,]]></description>

        

            <jf:creationDate>Feb 4, 2013 4:29:30 PM</jf:creationDate>
            <jf:modificationDate>Feb 4, 2013 4:29:30 PM</jf:modificationDate>
            <jf:author>milogardner@juno.com</jf:author>
            <jf:replyCount>2</jf:replyCount>
        </item>

        <item>
            <title>Re: Archimedes square root of 3</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=8248406&amp;tstart=0#8248406</link>

        

            <description><![CDATA[E.J. Dijkerhuis "Archimedes" page 435 discussed<br><br>(27^1/2)/3 in terms of a continuing fraction series<br><br>cited 3^1/2, 26/15, 265/153,]]></description>

        

            <jf:creationDate>Feb 4, 2013 3:07:40 PM</jf:creationDate>
            <jf:modificationDate>Feb 4, 2013 3:07:40 PM</jf:modificationDate>
            <jf:author>milogardner@juno.com</jf:author>
            <jf:replyCount>3</jf:replyCount>
        </item>

        <item>
            <title>Re: Archimedes square root of 3</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=8138403&amp;tstart=0#8138403</link>

        

            <description><![CDATA[Archimedes estimated pi by<br><br>22/7 &gt; pi  &gt; 223/71<br><br>1. the method scaled 22/7 by 10/10 = 220/70<br><br>2.obtained the lower limit by]]></description>

        

            <jf:creationDate>Jan 24, 2013 10:17:05 AM</jf:creationDate>
            <jf:modificationDate>Jan 24, 2013 10:17:05 AM</jf:modificationDate>
            <jf:author>milogardner@juno.com</jf:author>
            <jf:replyCount>4</jf:replyCount>
        </item>

        <item>
            <title>Re: Archimedes square root of 3</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=8114692&amp;tstart=0#8114692</link>

        

            <description><![CDATA[Archimedes' considered <br><br>1. (a + b)^2 = a^2 + 2ab + b^2 <br><br>in all three STEPS<br><br>and in STEP 2 <br><br><br>2. error 1  x/y]]></description>

        

            <jf:creationDate>Jan 20, 2013 12:53:32 PM</jf:creationDate>
            <jf:modificationDate>Jan 20, 2013 12:53:32 PM</jf:modificationDate>
            <jf:author>milogardner@juno.com</jf:author>
            <jf:replyCount>0</jf:replyCount>
        </item>

        <item>
            <title>Re: Archimedes square root of 3</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=8091671&amp;tstart=0#8091671</link>

        

            <description><![CDATA[(1251/780)^2 &gt; 3 &gt; (265/153)^2<br><br>(1251/780)^2  is accurate to 1/608400 = .000001644<br><br>(265/153)^2  is accurate to 2/23409 =]]></description>

        

            <jf:creationDate>Jan 17, 2013 2:22:08 PM</jf:creationDate>
            <jf:modificationDate>Jan 17, 2013 2:22:08 PM</jf:modificationDate>
            <jf:author>milogardner@juno.com</jf:author>
            <jf:replyCount>1</jf:replyCount>
        </item>

        <item>
            <title>Re: Archimedes square root of 3</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=8082935&amp;tstart=0#8082935</link>

        

            <description><![CDATA[references include <br><br>1. <a href="http://planetmath.org/encyclopedia/EgyptianAndGreekSquareRoot.html"]]></description>

        

            <jf:creationDate>Jan 16, 2013 11:17:44 PM</jf:creationDate>
            <jf:modificationDate>Jan 16, 2013 11:17:44 PM</jf:modificationDate>
            <jf:author>milogardner@juno.com</jf:author>
            <jf:replyCount>0</jf:replyCount>
        </item>

        <item>
            <title>Archimedes square root of 3</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=8082927&amp;tstart=0#8082927</link>

        

            <description><![CDATA[Archimedes' square root of 3 problem cited limits<br><br>(1271/780)^2 &gt; 3 &gt; (265/153)^2<br><br>A. The higher limit 1251/780 was calculated in]]></description>

        

            <jf:creationDate>Jan 16, 2013 11:14:12 PM</jf:creationDate>
            <jf:modificationDate>Jan 16, 2013 11:14:12 PM</jf:modificationDate>
            <jf:author>milogardner@juno.com</jf:author>
            <jf:replyCount>8</jf:replyCount>
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