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http://mathforum.org/kb/thread.jspa?messageID=6756303&tstart=0#6756303
> > Two circles of diameter (d) and (2*d) overlap (not > > over the centres) > > so that they have a]]>Jun 17, 2009 2:06:06 AMJun 17, 2009 2:06:06 AMavniu66@hotmail.com0Re: Overlapping circles
http://mathforum.org/kb/thread.jspa?messageID=6753917&tstart=0#6753917
> Two circles of diameter (d) and (2*d) overlap (not > over the centres) > so that they have a common chord of]]>Jun 15, 2009 11:01:46 PMJun 15, 2009 11:01:46 PMontadian@hotmail.com1Overlapping circles
http://mathforum.org/kb/thread.jspa?messageID=1087456&tstart=0#1087456
follow the thread.

At 07:00 PM 7/22/03 -0400, you wrote: Jul 23, 2003 11:51:16 AMJul 23, 2003 11:51:16 AMmary@krimmel.net1Overlapping circles
http://mathforum.org/kb/thread.jspa?messageID=1087454&tstart=0#1087454
yet to find the diameters (d) and (2*d) in terms of (s) and (c).]]>Jul 22, 2003 7:00:09 PMJul 22, 2003 7:00:09 PMontadian@hotmail.com2Re:Overlapping circles
http://mathforum.org/kb/thread.jspa?messageID=1087452&tstart=0#1087452
such a complex final equation. Can you tell me what "k" is? and what is]]>Jun 9, 2001 2:21:32 PMJun 9, 2001 2:21:32 PMontadian@hotmail.com0Re: Overlapping circles
http://mathforum.org/kb/thread.jspa?messageID=1087451&tstart=0#1087451
> > Hello W.H., > > The equation I get is: s = sqrt(d^2-c^2)/2 +]]>Jun 9, 2001 7:48:47 AMJun 9, 2001 7:48:47 AMvze2f978@mail.verizon.net1Re: Overlapping circles
http://mathforum.org/kb/thread.jspa?messageID=1087453&tstart=0#1087453
> Two circles of diameter (d) and (2*d) overlap (not over the > centres) so that they have a common]]>Jun 6, 2001 6:03:56 PMJun 6, 2001 6:03:56 PMrostamian@umbc.edu3Re: Overlapping circles
http://mathforum.org/kb/thread.jspa?messageID=1087450&tstart=0#1087450
The equation I get is: s = sqrt(d^2-c^2)/2 + sqrt(4*d^2-c^2)/2 + 3*d/2. I don't think it is easy to solve for d, so I didn't]]>Jun 6, 2001 3:24:31 PMJun 6, 2001 3:24:31 PMdklinkenberg@hvc.rr.com2Overlapping circles
http://mathforum.org/kb/thread.jspa?messageID=1087449&tstart=0#1087449
so that they have a common chord of length (c). The measurement across the]]>Jun 6, 2001 10:37:06 AMJun 6, 2001 10:37:06 AMontadian@hotmail.com9