My guess is that the approach Dave had in mind was more
a^2 - (a-1)^2 = (a - (a-1)) (a + (a-1)) = (1)(2a - 1)
At 08:36 PM 9/28/2012, Robert Hansen wrote:
a^2 - (a-1)^2 = a^2 - (a^2 - 2a
+ 1) = 2a - 1 = 13.04822...
This is a very good point, work the algebra FIRST. I wonder how many
algebra teachers are even capable of concocting such a problem? Working
backwards and making sure that 2*a doesn't require any more than single
digit math (no digit greater than 4). I have to think about this. This
works well with large integers as well, with the same condition on the
Lou, what do you say to problems like this with regards to our prior art
Ha, calculators are allowed. Calculators with 70 digits of precision I
On Sep 28, 2012, at 5:51 PM, "Dave L. Renfro"
> Robert Hansen wrote:
>> I want to try something different. I want everyone to
>> problems for a hypothetical algebra 2 exam. You can
>> just topics if you wish though I would like see examples as
>> I am going with algebra 2 rather than algebra 1 because I
>> the line is more well defined.
> I only have a few moments before I need to leave to tutor
> someone, but here's a somewhat silly one off the top of
> my head:
> Determine the exact value of a^2 - b^2 if
> a = 7.0241132301442003123012230341430201
> b = 6.0241132301442003123012230341430201
> Calculators are allowed.
> Dave L. Renfro