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Topic: Help with probability&stat problem
Replies: 11   Last Post: Jun 11, 2007 11:07 PM

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 briggs@encompasserve.org Posts: 404 Registered: 12/6/04
Re: Help with probability&stat problem
Posted: Jun 11, 2007 1:02 PM

In article <1181579232.176149.92070@c77g2000hse.googlegroups.com>, tutorny <tutorny@gmail.com> writes:
> I am looking at solving the following problem:
>
> Past records show that at a given college 20% of the students who
> began as psychology majors either changed their major or dropped out
> the school. An incoming class has 110
> beginning psychology majors. What is the probability that as many as
> 30 of these students leave the psychology program?

I read that as the probability that 30 or more leave. You've apparently
read it as the probability that 30 or fewer leave. The longer I look
at the question, the less sure I am which of us is correct.

> I think that I can solve it using the normal approximation to the
> binomial probability distribution, as follows:
>
> n =110, p = 0.20
> mean = u = np = 110*0.20 = 22
> standard deviation = s.d. = (n*p*q)^.5 = (110*.20*.80)^.5 = 4.1952

Looks reasonable. And I personally agree that the normal approximation
is a good fit for this kind of question. Especially since we're not
way out on the tail of the curve.

> We want P(x <=30)
>
> When x = 30, z = (x - u)/s.d = (30 - 22)/4.1952 = 1.9069

Here, I think you've committed a fencepost error. If you're treating
a normal distribution as if it were a discrete histogram then you
want to put your cutoff points between the bars on the histogram, not
in the middle of the bars. You want to look at x=29.5 or x=30.5.

You decide whether to use the x=29.5 or the x=30.5 cutoff by considering
whether the case when x=30 is included or excluded in the set of cases
you are looking for.

Think about it this way. You're approximating p(x=30) in the
discrete case by p(x<=30.5) - p(x<=29.5) in the continuous model.

Or think about it this way. If you were asked for the probability
that x is 30 or more, do you want the answer to be the complement
of the probability that x is 30 or less? It will be if you use
p(x>=30) and p(x<=30) as your respective estimates. Or do you want the
non-zero probability that x is 30 exactly to figure in somehow?
That's where the 29.5 and 30.5 make themselves useful.

Date Subject Author
6/11/07 tutorny
6/11/07 briggs@encompasserve.org
6/11/07 tutorny
6/11/07 Randy Poe
6/11/07 tutorny
6/11/07 Bruce Weaver
6/11/07 tutorny
6/11/07 Bruce Weaver
6/11/07 C6L1V@shaw.ca
6/11/07 Randy Poe
6/11/07 tutorny
6/11/07 Nick