The Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Math Forum » Discussions » sci.math.* » sci.math

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: Division without the axiom of choice
Replies: 10   Last Post: Jan 12, 2013 4:51 PM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
Butch Malahide

Posts: 894
Registered: 6/29/05
Re: Division without the axiom of choice
Posted: Jan 12, 2013 4:51 PM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

On Jan 12, 2:40 am, wrote:
> This is a much clearer exposition than the Conway/Doyle one I now completely understand the proof.  It might be worthwhile submitting your argument for publication (I'm guessing that it's your proof or your exposition).

I'm glad you understand the proof now. I'm guessing that my equine
exposition is goofy enough to be original. I'm guessing that the proof
I posted is *not* new, but I wouldn't know; I haven't had time to
study the Conway-Doyle proof yet (thanks for the reference), and I
haven't seen any of the other proofs. Anyway, I don't think it's
worthwhile to submit it for publication; it's a rather specialized
result for which other proofs are available.

Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2018. All Rights Reserved.