
Re: A nonconventional ListContourPlot
Posted:
Feb 25, 2013 2:19 AM


ContourPlot[Sin[x + y^2], {x, 2, 2}, {y, 1, 1}, ColorFunction > ColorData["DarkRainbow"]]
??
Rather, why do you want to sample at your strange set of x,y values? Is the z expression just a standin for actual measure values? You might try Interpolation with InterpolatingOrder > 1, but the results in this case do not seem promising.
David Park djmpark@comcast.net http://home.comcast.net/~djmpark/index.html
From: Luiz Melo [mailto:lmelo@ufsj.edu.br]
Good day,
x[a_,b_] = a*b; y[a_,b_] = Cos[a^2 + b]; z[a_,b_] = Sin[a + b^2];
data = Table[{x[i,j], y[i,j], z[i,j]}, {j, 1, 1, 0.1}, {i, 2, 2, 0.1}];
For the table above, is it possible to see a ListContourPlot of the z component as a function of x and y (the values of x and y on the horizontal and vertical axes, respectively)?
Thank you in advance Luiz Melo

