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Topic: The Codes of Saqqara Step Pyramid - Part 16 - Coordonations of Zoser's and Cheops's Pyramids,
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 Ion Vulcanescu Posts: 342 Registered: 12/3/04
The Codes of Saqqara Step Pyramid - Part 16 - Coordonations of Zoser's and Cheops's Pyramids,
Posted: Oct 19, 2004 1:26 AM

(See COPYRIGHT NOTICE at the end of the Research Data)

Preface
THE COORDONATION
of Saqqara Step Pyramid and Cheops Pyramid.

This Coordonation was possible due to my prior years
discovery of the fact that the Saqqara Step Pyramid was not
having only the now seen 6 steps but another step - the 7th- which
was WITH INTENTION not built by the architect Imhotep,
and also the realization by me that Saqqara Step Pyramid
in Spiritual Form
WAS CONTINUING INTO UNDERGROUND
8 more steps that through Design they were incorporated
into the Cheops Pyramid.

Through philosophy I realized the fact that between the reigntime
of Zoser and Cheops was a just cca. 50-100 years and thus
THE EGYPTIAN BODY OF KNOWLEDGE
on which the Saqqara Step Pyramid was designed and built
was somehow PRESENT in
THE DESIGN OF CHEOPS PYRAMID.

Now you shall see the Coordonation between Zoer's and Cheops's
pyramids. As you are by now familiar with the fact that Zoser's
Step Pyramid is concluded by the scientists to have a volume of
330400 cubic meters, and Cheops Pyramid of 2592000 cubic meters,
myself I call these 330400 and 2592000 as UNITS OF ONE (ufo)
as to differenciate them of the CUBIC METERS.

THE TABLE OF COORDONATION OF ZOSER AND CHEOPS PYRAMIDS
Part A
A-----B----------C---------D---E-----F
1-----768 x3 =-2304 :1 = 2304+56 = 2360
2----6144x3 =-18432 :2 = 9214+224 = 9440
3---20736 x3 = 62208 :3 = 20736 + 504 = 21240
4---49152 x3 = 147456 :4 = 36864 + 896 = 37760
5---96000 x3 = 288000 :5 = 57600 + 1400 = 59000
6--165888 x3 = 497664 :6 = 82944 + 2016 = 84960
7--263424 x3 = 790272 :7 = 112896 + 2744 = 115640
----------------------------------------------------------
Part B
8--442368 x3 =1327104 :8 = 165888 + 4032 = 169920
9--559872 x3 = 1679616 :9 = 186624 + 4536 = 191160
10-768000 x3 = 2304000 :10 = 230400 + 5600 = 236000
11-1022208 x3 = 3066624:11 = 278784 + 6776 = 285560
12-1327104 x3 = 3981312 :12 = 331776 + 8064 = 339840
13-1687296 x3 = 5061888 :13 = 389376 + 9464 =398840
14-2107392 x3 = 6322176 :14 = 451584 + 10976 = 462560
15-2592000 x3 = 7776000 : 15 = 518400 + 12600 = 53100

Now look in the Column "F" at Step 1 of 2360 ufo. These 2360
ufo were SUNK in all other 6 remaining steps of Zoser's Pyramid
IN SUCH WAY
that the voume of 330400 remains THE SAME.

Note where is located "2592000 ufo" it is on step 15. This indicates
that the Step 15 is on the Ground and the Step 1 is on the top of
the pyramids. The Sinking of the 1st step in Zoser's Pyramid
indicates that the top of Zoser's pyramid is Step 2.

Look now in coumn "B" at step 15. See that "7776000 ufo"
Do you remind what is this 7776000 in the Sumerian Geometric Point
of the Sumerian Year ? Sure...it is the Side of such Geometric Point:

SUMERIAN YEAR = 31104000 Seconds = a square
Square Side = 7776000 Seconds
Square Perimeter = 3110400 Seconds

Let's see now the step-ratio of Evolution of Column C,
and Separe each step-ratio by her step value as follows:
Note "THE ANOMALY" of step 2....
It suppose to be "4x2 = 8" but insted is "4x1 = 4"
1-----1x 1 = 1
2-----4x 1 = 4---Note "The KEY TO CONCEPT" here !
3-----9x 3= 27
4----16x 4= 64
5----25x 5= 125
6----36x 6= 216
7----49x 7= 343
8----72x 8= 576
9----81x 9 = 729
10-100x10=1000
11-121x11=1331
12-144x12=1728
13-169-13=2197
14-196x14=2744
15-225x15=3375
------------------
1248
Note this "1248" which is the sum of all steps seen above "225"

Now let's see another Key of "140"

The sum of steps 1thru 15 of column D is 2875392
The sum of steps 1 thru 7 of column D is 322560
The sum of steps 8 thru 15 of column D is 2552832
Thus we have 2875392 - 322560 = 2552832

The sum of steps 1 thru 15 of column E is 69888
The sum of steps 1 thru 7 of column E is 7840
The sum of steps 8 thru 15 of coumn E is 62048
Thus we have 69888 - 7840 = 62048

The sum of steps 1 thru 15 of Coumn F is 2945280
The sum of steps 1 thru7 of coumnF is 330400
The sum of step 8 thru 15 of coumn F is 2614880
Thus we have 2945280 - 330400 = 2614880

Now let' see the implication of the Key Code 2304 + 56 = 2360

322560 : 2304 = 140 for steps 1 thru 7
7840 : 56 = 140 for steps 1 thru 7
440400 : 2360 = 140 for steps 1 thru 7

2552832 : 2304 = 1108 for steps 8 thru 15
62048 : 56 = 1108 for steps 8 thru 15
2614880 : 2360 = 1108 for steps 8 thru 15

2875392 : 2302 = 1248 =1108 + 140
69888 : 56 = 1248 = 1108 + 140
2945280 : 2360 = 1248 = 1108 + 140

or we can see the Coordonation between Zoser's and Cheops's
pyramids as follows:
2875392 + 69888 = 2945280
322560 + 7840 = 330400 = Zoser's Pyramid Volume
2552832 + 62048 = 2614880

Please, be aware that Zoser's Pyramid can be seen in many
other volumes and even this "330400" can be seen in many
forms.The "330400" that I now present
IT IS NOT THE FINAL FORM
for that I have TO SUNK the 1st step.

Let's then Sunk this 1st Step and through this sinking see what
is that "140" Code Key that appeared.

THE SINKING OF THE TOP STEP OF SAQQARA STEP PYRAMID

Part A
Step 1
Make the sum of all 7 steps which is 28.
1+2+3+4+5+6+7 = 28 units
Step 2
Calculate the Ratio of Sinking
of the 1st step in the rest of 27 steps as
ONE : (28-1) = .037037037 = the Ratio of Sinking
Step 3
Apply the Ratio of Sinking to each step 2 thru 7.
See this application in Part B

Part B
1/27 x 2 = .074074074...Step #1
1/27 x 3 = .111111111...Step #2
1/27 x4 =.148148148...Step #3
1/27 x5 = .185185185...Step #4
1/27 x6 = .222222222...Step #5
1/27 x7 = .259259259...Step #6
...and now you have the Deisgn-View of the really phisical steps of
Saqqara Step Pyramid.

Let's then see the Really view of the Volume "2360" sunk into
these 6 steps. For this we have to separe this "2360" in 27 parts
as 2360/27 = 87.4074074, and apply it as:

Step # 1-----9440 + (2360/27 x 2) = 9614.81485
Step # 2-----21240 + (2360/27 x 3) = 21502.222
Step # 3-----37760 +(2360/27 x 4) = 38109.62963
Step # 4 -----59000 + (23560/27 x5) = 59437.03704
Step # 5-----84960 + (2360/27 x6) 85484.4444
Step # 6------115640 + 2360/27 x7) = 116251.8519
Total Vollume 328040 + (-----2360---) = 330400

...and now let's REDUCE each step of Saqqara Step Pyramid to
1.1111....which prooves that the scientists of this era in time
knew the fact that the Geometrical Proportion have to be
handled through 1.11111111... and not through .000...1 as
CALCULUS use in its incrporated Concept called
THE ASSUMING CONCEPT
which is no more and no less then
THE HISTORICAL PROOF
of

Step # 1-----9614.81485 : 2360 : 55 x 15 = 1.111...
Step # 2-----21502.2222 : 2360 : 82 x 10 = 1.111...
Step # 3----38109.62963 : 2360 : 109 x 7.5 = 1.111...
Step # 4-----59437.03704:2360 : 136 x 6 = 1.1111...
Step #5--------85484.444 : 2360 : 163 x 5 = 1.11111...
Step # 6 ----116251.8519 : 2360 :190 x 4.28571428 = 1.111

...and what is this 4.28571428 ?
It is The altitude of Thebes divided by 6
25 degrees,42 minutes,51,43 seconds = 25.71428571
27.71428571 : 6 = 4.285714285

...and what was the altitude of Thebes?
It was the 14th part of the Earth's Circumference
360 : 25.71428571 = 14

..and what is 14?

Well... now I have to STOP here !
If there is a mistake here or there, please disregard it and
keep following the Concept.
The presentation of the Research Data shall continuu soon in Part 17.

The Research Data herein presented is part of
THE AMERICAN CIVILIZATION'S GEOMETRY
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Ion Vulcanescu - Philosopher
Independent Researcher in Geometry
Rediscoverer of the Lost Geometric Point of Ancient Civilizations
Rediscoverer of the Lost Sumerian Geometric PI value 3.146264371...
Author,editor and Publisher of
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