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Re: integration help
Posted:
Sep 14, 2006 9:16 AM


John wrote: > I've written an analytic routine to integrate the function > > f(x,y) = 1/sqrt((xxo)^2+(yyo)^2) > [...] > Over the > triangle 0<=x=<1, 0<=y<=x and (xo,yo)=(2/3,1/3), my analytic routine > result is > > 2.4072299231640093 > > Maxima returns (dblint_x=dblint_y=1000) > > 2.406741250203651 >
Maple 10 gives: I = 1/3*2^(1/2)*ln(3+5^(1/2)*2^(1/2))1/3*ln(2+5^(1/2))+(4/31/6*2^(1/2))*ln(2^(1/2)1)+ln(2+5^(1/2))2/3*arctanh(2/5*5^(1/2))2/3*arctanh(1/2*2^(1/2))1/6*2^(1/2)*ln(1+2^(1/2)) i.e. I = 2.4072299231640097043
It seems that your routine is much more accurate than Maxima's one!
Regis LEBRUN



