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Re: Calculus Problem  Can You Help?
Posted:
Oct 15, 2006 9:29 PM


On Mon, 16 Oct 2006 01:16:18 GMT, "[Mr.] Lynn Kurtz" <kurtzDELETETHIS@asu.edu> wrote:
> >On 15 Oct 2006 17:27:06 0700, "Bill" <bill@afplaza.com> wrote: > >>Hello, >> >>I am looking for help with a calculus problem. Can you take a look and >>see if you can help? >> >>Since I have a hard time getting all the little characters straight in >>the newsgroups, I just posted the problem on a webpage I have space on. >> It is located at www.afplaza.com. >> >>I am clueless when it comes to Calculus so I am hoping someone alot >>smarter then me can help us out. Problem 13 only. She has shown her >>work and knows the answer  she is confused about how to handle the >>middle of the problem. >> >>Thanks in advance! >> >>Bill >>www.afplaza.com > >It doesn't require integration by parts. She has u = e^(x^3) and du = >3x^2 dx so she should just substitute u for the e^(x^3) and (1/3)du >for the x^2 dx. It is a straight substitution. > >Lynn
Correction, I read it too quickly. With her choice of u her du should be du = 3x^2e(x^3) dx so her integrand is just (1/3)du.
Alternatively she could try u = x^3, du = 3x^2 dx so her integrand becomes (1/3) e^u du.
Both methods lead to the same answer.
Lynn



