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Topic: Differentiation
Replies: 8   Last Post: Sep 17, 2007 6:31 AM

 Messages: [ Previous | Next ]
 Darrell Posts: 251 Registered: 12/6/04
Re: Differentiation
Posted: Sep 16, 2007 9:13 PM

"fk378" <glam422@gmail.com> wrote in message
news:33546210.1189959326672.JavaMail.jakarta@nitrogen.mathforum.org...
> hello all!
>
> I'm having trouble with this problem:
> Differentiate sin(t) + (pi)cos(t)
>
> So, I have f'(x) of sin(t) = cos(t)
> Now what do I do with the (pi)cos(t) part? Do I say that the slope of pi
> is zero, therefore the derivative of (pi)cos(t) is 0, then the answer
> would be just sin(t) for the whole equation.
>
> OR
>
> Leave pi there, and have f'(x) of cos(t)= -sin(t) so that would make:
> cos(t) + (pi)(-sin[t]) ???
>
> thank you!!

The latter, which can be written cost(t)-(pi)sin(t). Pi is constant but
pi(-sin(t)) is not, anymore than (1)(cos(t)) is even though 1 is constant.

--
Darrell

Date Subject Author
9/16/07 fk378
9/16/07 Compendium
9/16/07 fk378
9/16/07 Darrell
9/17/07 Frederick Williams
9/16/07 [Mr.] Lynn Kurtz
9/16/07 fk378
9/16/07 Darrell
9/17/07 Frederick Williams