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Topic: The impossible circle strikes again
Replies: 11   Last Post: Jun 23, 2009 5:49 PM

 Messages: [ Previous | Next ]
 Jonathan Halabi Posts: 119 Registered: 8/16/08
The impossible circle strikes again
Posted: Jun 21, 2009 11:03 PM
 att1.html (0.8 K)

IA #34 reminds me of an old Math B question. Who remembers June 2004, #33?
http://www.nysedregents.org/testing/mathre/regentmathb.html

In this case, a chord parallel to the diameter is 3/4 the length of the
diameter. Call the Diameter 16, the radius 8, the chord 12. From the center
of the circle to the endpoint of the chord is a radius, 8. Drop a
perpendicular from the endpoint of the chord to the diameter. It meets the
diameter 6 units from the center. By Pythagoras, the perpendicular is
2sqr(7) units long.

Or, try this. Let the radius be 8, the perpendicular be 4, then the
half-chord (by Pyth) is radical 48.

Oops.

Thanks to Pete G. for pointing this out.

Jonathan Halabi
HS of American Studies
the Bronx

Date Subject Author
6/21/09 Jonathan Halabi
6/22/09 Tom Kenyon
6/22/09 ElizWaite@aol.com
6/23/09 Tom Kenyon
6/23/09 Jonathan Halabi
6/23/09 ElizWaite@aol.com
6/23/09 Dee Jones
6/23/09 Evan Romer
6/22/09 Kate Nowak
6/22/09 Loretta Boyce
6/22/09 Kate Nowak
6/23/09 Kevin McCarthy