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Re: A different geometry problem
Posted:
Dec 13, 2010 1:21 AM


Philippe,
Thank you for your explanation of the emphases; it's simpler than I expected it to be.
It seems to me that Sujeet's and Peter's solutions are distinct and also that I have two distinct nonsolutions which meet the angles given but not the noisosceles requirement. That's four! I am looking forward to the allinone solution you will demonstrate.
Also, I'm hoping that someone will take up Sujeet's desire for problems using angles which are multiples of pi/7. Are these adventitious angles? I have much to learn.
Your diagrams are a great help.
Mary



