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Another Triangle division.
Posted:
Dec 17, 2010 10:59 PM


An isosceles triangle has a larger base than its sides. A line is drawn from its apex to its base with a further line drawn at 90 degrees to that line so as to finish at the triangle side. Both lines are of equal length. We now have the triangle divided into 3 equal areas. Find the ratio of the triangle side to its base. An interesting solution involves the use of the trigonometrical identity: tan(alpha+beta)= (tan alpha+tan beta)/(1tan alpha*tan beta)



