On Nov 18, 6:54 am, Paul Cardinale <pcardin...@volcanomail.com> wrote: > On Nov 14, 1:57 pm, Tom Roberts <tjrob...@sbcglobal.net> wrote: > > > On 11/13/11 11/13/11 - 3:34 PM, james thomas wrote: > > > > [... uninformed nonsense] > > > Replying to the subject: In GR a black hole DOES "pull light backward". > > > One of the best definitions of the event horizon of a black hole is that it is a > > closed trapped surface. That is, the horizon is closed (has no boundary), and > > trapped -- every non-spacelike (timelike or null) trajectory that intersects the > > surface goes into its interior. That means no object can escape, and even light > > that is initially emitted outward from the horizon actually goes inward. AFAICT > > that contradicts your claim "cannot pull light backward". > > > Tom Roberts > > If an outward facing light source were to free fall into a black hole, > wouldn't it be that the light emitted after crossing the event horizon > would be moving outward with respect to the emitter, and inward with > respect to the center of black hole? > And, with respect to the falling emitter, the sliver of light emitted > at the event horizon would be co-moving outward with the event > horizon, and with respect to the center of the BH, be stuck at the > event horizon? > What happens to that sliver of light as other material falls into the > BH, pushing the event horizon outward? > > Paul Cardinale
If light is not subject to being slowed down a black hole does not work. If light is straight outward from gravity center it could never boomarang or curve back.