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Patrick
Posts:
4
Registered:
2/12/12
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Re: Simple non-linear equation solving question
Posted:
Feb 13, 2012 12:32 AM
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Thanks for the response. My Matlab version is 7.10.0 (R2010a).
The full code:
clear all
clc
close all
x=[-.5:.01:1];
m=-x.^3 + (sin(x)).^2;
plot(x,m)
clear x
x = sym('x');
solve(-x.^3 + (sin(x)).^2)
Which provides a plot, and:
ans =
matrix([[0]])
From the plot, I can see that there is also a solution at about 0.803.
Thanks again...
"Nasser M. Abbasi" <nma@12000.org> wrote in message <jha64h$kls$1@speranza.aioe.org>...
> On 2/12/2012 10:42 PM, Patrick wrote:
> > Hi,
> >
> > I'm trying to solve the following non-linear equation: 0=-x^3 + (sin(x))^2
> >
> > EDU>> solve(-x^3+sin(x)^2)
> >
> > ans =
> >
> > matrix([[0]])
> >
> > By graphing this equation, it appears that there are solutions at 0 and 0.803. What am I doing wrong?
> >
> > Thanks...
>
> Which verssion do you have?
>
> on mine:
>
> MATLAB Version 7.12.0.635 (R2011a)
>
> I get
>
> --------------------
> EDU>> syms x
> solve(-x^3+sin(x)^2)
>
> ans =
>
> 0
> ----------------------
>
> matrix([[0]]) means zero solution also? i..e a vector, which one
> entry, and that entry is zero. so same answer I have.
>
> So, I do not know how you got 0.803 there. What command you used
> to plot? Please show complete code you did, not one line.
>
> --Nasser
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