I thought the equation is z = asin(2*y-x) with boundary conditions of y = (x-1)/2 or y = (x+1)/2. How can I solve for the possible x (or y values) so that pi/2<=z<=pi/2?
"Matt J" wrote in message <email@example.com>... > "jun" wrote in message <firstname.lastname@example.org>... > > Hi All > > > > How can I solve a multivariable function using matlab? I have no idea which function should be used. > > > > Here is an example question: > > f(x,y) = asin(2*y-x) > > so the boundary would be y = (x-1)/2 or y = (x+1)/2 > > and z = f(x,y) would be -pi/2<=z<=pi/2 > > How can I define the boundaries in matlab and get the values of x or y? > ================= > > I don't think anyone understands your question, which is why repeatedly reposting your original problem description isn't helping you. > > It is not clear what's to be solved here because you've presented a function, but no equation. What is the equation to be solved?