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Topic: numerical challenge, part 2
Replies: 2   Last Post: Nov 2, 2012 6:13 PM

 Messages: [ Previous | Next ]
 Phil Carmody Posts: 2,219 Registered: 12/7/04
Re: numerical challenge, part 2
Posted: Nov 2, 2012 6:13 PM

Ben Bacarisse <ben.usenet@bsb.me.uk> writes:
> I know this is now an old post but a recent reply made me look again...
>
> Phil Carmody <thefatphil_demunged@yahoo.co.uk> writes:

> > eric.jacobsen@ieee.org (Eric Jacobsen) writes:
> >> On Tue, 30 Oct 2012 19:50:19 -0700, William Elliot <marsh@panix.com>
> >> wrote:
> >>

> >> >On Tue, 30 Oct 2012, RichD wrote:
> >> >

> >> >> What is the sum of the digits of 3 ^ 1000?
> >> >
> >> >The sum of the base 3 digits of 3^1000 is 1.

> >
> > True.
> >

> >> >The sum of the base 9 digits of 3^1000 is 1.
> >>
> >> That's clever. If I were interviewing, asked this question, and got
> >> this answer I'd be favorably impressed.

> >
> > Nope, it's 3.
> >
> > 3^1=3
> > 3^2=10
> > 3^3=30
> > 3^4=100
> > 3^5=3000
> > 3^6=10000
> > 3^7=30000
> > 3^8=100000
> > 3^10=300000

>
> It looks like you've added a 0 from 3^5 upwards.

Good catch. I was getting a bit bored by that stage, as you can imagine.

Phil
--
Regarding TSA regulations:
How are four small bottles of liquid different from one large bottle?
Because four bottles can hold the components of a binary liquid explosive,
whereas one big bottle can't. -- camperdave responding to MacAndrew on /.

Date Subject Author
11/2/12 Ben Bacarisse
11/2/12 Phil Carmody