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Registered: 9/1/10

The Decimal Apples Problem
Posted: Dec 8, 2012 9:40 AM

Plain Text

1 is a number > 0 numbers in decimal.
Numbers are infinite. There are infinite decimal numbers.
The term symbols xy, x*y, x(y) multiply number x by number y to
produce a result often unequal to zero. Possible multiplication is
also defined as the process of multiplying numbers x and y does not
equals z, unless x or y or both x and y equal zero. Or alternatively
we say x and y does not equal 0, or zero.

When a number is decimal say for instance a number n is a decimal
number if n>0<1.
If a first number is 1/4 then it is the decimal number .25. We will
define it as x.
And if a second number is 5/10 it is the decimal number .5. At present
many mathematicians and related sciences hold it to be mathematically
consistent with logic to say multiplying a whole number by a decimal
is the same as dividing it. This is incorrect by the law of mass
transivity.

The law of mass transivity states the mass of an object whole holds
true to a numerical expression independent of the single quantity
designation.

Here is my proof:

If I have 2/3 of an apple. I write it as .66. To show what this looks
like in nature I will use the letter r once for each piece of a whole
apple written below:

rrrr
rr

is a whole apple. Now I write what is 5/10 or .5 of an apple using the
same expression, by logic would mean should be exactly half of the
above size or rather

rrr

but since each apple piece is qual to .11 to show

rrrr
rr is a whole apple

but

rrrr (.55) apple is greater than rrr or 1/2 the whole apple.

The solution is to consider the inputs independent of quantization as
I state per mass transivity property:

If rrrrrr is a decimal apple and we rrrrr is a lesser decimal
apple their multiplication should be rrrrrr x rrrrr

or

rrrrrr
rrrrrr
rrrrrr
rrrrrr
actually produces 30 * .11 = 3.33 apples

since each apple piece is equal to .11 apple the result of the
multiplication of .5 times .6 apples 30 pieces of apple each equal to
11/100ths of an apple translated to 3 and 1/3 apples.

Physics at present writes multiplicaiton of apple b and apple a as .8*.
9=.72
So the apple shrinks to a smaller apple an one disappears? No. This
assumption is a fallacy because of this truth: If the above
representations where of bushels of apples say 9 apples on the left
and 8 apples on the right the result of their interaction we would
describe as producting 72 apples. Nature needs to recognize our
designation of matter independent of our standard measurement in
mathematics. 9/10 of an apple is still 9/10 of 10/10 of a whole apple
and the apple generally holds the same qualities of interaction in
terms of weight and velocity relative to size even though less than a
whole apple is represented. For proof take a whole apple and throw it
against a wall. Then do the same with an apple with a bite out of it
and observe the laws of physics hold. Now, here is the proper proof of
what the multiplication of the .9*.8 apples should be:

Suppose a whole apple

apples the result we write is:

RRRRRRRRRRRRRRRRRRRRRRRRRRR
apples.

Now do the same with the small apple decimal portions:

.9 and .8

r r
rrrrr x rrrrr
rrr rr
apples the result is

Signed,
Musatov