
Re: The nature of gravity
Posted:
Jan 4, 2013 1:45 PM


The proton opposite GM products, looking something like 29.6906036, are formed from the formula 4[{h(c/2)^4}/2]^0.166r/(Gc/2)^0.5. In this inbetweener system we have G at 6.4487303x10^11 and h at 6.854931784x10^34.
So the above formula goes something like this: h/(c/2)^4=0.346071604. Divide by 2=0.173035802. 4(0.173035802)^0.1666r=4x0.746487799=2.985950838. 2.985950838x(Gc/2)^0.5=30.37037806. Not the 30.71607957 mentioned earlier. That turns out to be a sideshow, the square root of the original difference, (x). But, as you can see from above, the proton monitor and opposite are programmed from a process involving the sixth root, not square root. However, 30.71607957 is a valid candidate for selection as a comparative template because it has maintained consistent proportionality in terms of (x) and the current constant values within the inbetweener model.
There is another numerical sequence, within varying mass models, that involves numbers similar to 29.6906036. You may remember that in the protonic model the timescale mass, 1.080624035x10^35, was the cube of 4.763120195x10^11 and which when this is squared produces the proton Compton frequency, 2.2687314x10^23. The GM products of each of those numbers, 4.763120196x10^11 was 29.6906036. But, if we take the timescale mass of the inbetweener model, 6.736x10^24/Local G we get 1.044546847x10^35 inbetweener mass units. The cube root of 1.044546847x10^35 is 4.709512719x10^11. Multiply this by local G, 6.4487303x10^11, and we get 30.370378. (30.370378)^3 is 2.801241586x10^4. Multiply this by c^2 then divide by local h, 6.854931784x10^34, and you get 3.672728673x10^54. This is the base of the Planck field, or the Planck gravitational field, and it goes like this: (3.672728673x10^54)/G^3=1.3695132x10^85. The square root of this value is 3.70069336x10^42, which is the number of Planck lengths in one light second. If you work out the Compton wavelength of the mass 1.044546847x10^35 you will need to use the inbetweener h and you will find that it is 2.189044049x10^77m. Divide this into c and you have a Compton frequency of 1.369513x10^85. Which, of course, is the same as the Planck field. The difference is that Gravity is a surface phenomenon. A Schwarzschild sphere measuring one light second in diameter will have a surface area of 4pi(c/2)^2 or 2.823522667x10^17 square meters. Therefore, there are 1.369513x10^85 Planck areas on a spherical surface measuring 2.823522667x10^17 square meters. A Planck area measures (4pi)r^2 where r represents the Planck radius, some 4.05049x10^35m, making the Planck area 2.061698228x10^68m^2.
Back to the inbetweener system. If you study the phenomenon of 29.6906036 and its derivatives you will see that in the inbetweener system that the value for the proton monitor opposite GM product is the same as the number involved in the base of the Planck field, 30.370378. We can be pretty sure that this is the only mass model using the meter/second where this is the case and that there will be a difference between the two separate phenomena within each system proportionate to that particular system's difference with the inbetweener model. For instance, 30.370378/29.6906036=1.02289527, so we can expect the proton monitor opposite GM product in the protonic system to be (29.6906036)(1.02289527)^2=31.06571602. And, consequently, the SI system's kilogram/second model will be the reverse of the protonic version with (31.06571602)^3 as the base of the local Planck field and the proton monitor to be just that, the proton.

