Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Topic: explaining rest-mass in New Physics #1226 New Physics #1346 ATOM
TOTALITY 5th ed

Replies: 1   Last Post: Feb 13, 2013 10:35 PM

 Messages: [ Previous | Next ]
 plutonium.archimedes@gmail.com Posts: 18,324 Registered: 3/31/08
explaining rest-mass in New Physics #1226 New Physics #1346 ATOM
TOTALITY 5th ed

Posted: Feb 13, 2013 4:12 PM

In the textbook CHEM ONE by Waser, Trueblood, Knobler, 2nd ed., 1980,
page 307 is a picture of the
Debroglie waves for permitted waves and prohibited orbitals.

Now in New Physics, with the Maxwell Equations as axioms, that Quantum
Mechanics becomes a very small and tiny subset of the Maxwell
Equations. This can be seen already in the fact that if we sum up two
of the 4 Maxwell Equations we get all of the Schrodinger Equation of
quantum mechanics. If we sum up all 4 of the symmetrical Maxwell
Equations (containing magnetic monopoles) we get the Dirac equation
and a lot more than the Dirac Equation.

And this is also plainly seen that the Maxwell Equations is far more
than quantum mechanics because the Maxwell Equations started off as
relativistic, whereas quantum mechanics has to be made to be
relativistic.

But the lesson I want to dive into today is rest-mass.
Rest mass is a thorny and prickly subject in physics. Quantum
Mechanics has never been able to depict rest-mass from that of
particle and wave. Today, I want to make some progress on that front,
keeping in mind that no matter what, at page 1300 of New Physics I
will stop on that text. So I must be mindful of not wasting any posts.

In the prior post I wrote this:
So now, in New Physics, let us describe the motion of a photon and a
neutrino, where the neutrino is a longitudinal wave of magnetic
monopoles. And the photon is a double transverse wave of this:
E+ ?M+ M- ?   E-
I suppose I could depict the neutrino longitudinal wave as this:
...M+ M- ... M+ M- ... M+ M- >>>
When a photon is created, the E- and E+ cancel in destructive
interference leaving the photon particle in the direction of motion
along the axis of the double transverse wave, and the same for the M+
and M- component.

Now we can look at the picture in CHEM ONE on page 307 and imagine a
very short wavelength of a photon, a gamma ray and we can imagine that
the energy is so large in the gamma ray that it curves back around
forming a Debroglie closed loop. And by forming the closed loop, the
photon gamma ray became a electron and positron pair.

So we can begin to see how rest-mass is formed from a wave. And begin
to see how rest-mass particles cannot go at the speed of light because
to go at the speed of light means no closed loops.

Now the electron and positron are easily seen as closed loops, like
the wire loop in Faraday's law, but the proton is seen as a hollowed
out sphere or bent sphere shaped object (ellipsoid). So in the
electron, we have a loop or ring or wire loop shaped object and in the
proton we expect a hollowed sphere shaped object. So we can see how a
transverse wave, if its front edge is bent that it becomes a closed
loop. But can we picture a wave to where it is leading edge bent that
it becomes a hollowed sphere? Well, not with a single transverse wave,
but with a double transverse wave as depicted above, can we picture
that the two transverse components form a sphere rather than a ring
shape. The E+ with the M- forms one hemisphere and the E- with M+
forms the second hemisphere. Now when a photon double transverse wave
of a gamma ray forms a electron and positron, those two particles use
one hemisphere apiece, but when a photon becomes a proton (which I
have never heard happens due to lack of energy), but if we ever did
have the energy, the photon would form the proton, a newly created
proton by having the two hemispheres remain together forming a
hollowed sphere of a new proton, with the release of a electron of the
E-.

Anyway, the main point is that rest mass is formed when a wave going
at the speed of light becomes tripped up in some manner of the Maxwell
Equations, and at the point of tripped up, the wave
bends around forming a loop, a closed loop and this closed loop is
rest-mass. When a wave has no closed loops in its entirety, then it is
absent of rest-mass.

Now previously I spoke of the fact that charge, electric charge is
geometry and that E- is hyperbolic geometry, such as the electron is
hyperbolic geometry which means it is a closed loop of wire shape, and
that E+ was elliptic geometry shaped such as a hollow sphere. Now it
appears that magnetic monopoles are not closed loops but are waves of
Euclidean geometry just as photons are waves. However, the magnetic
dipole, such as magnets or Earth as a whole are dipoles and thus
closed loops of a sphere shape with rest-mass.

So rest-mass is a NonEuclidean geometry of charge
and having closed loops, while no rest-mass means a wave that is the
speed of light and no closed loops.

Now we have to ask, what trips-up a gamma ray photon to produce the
pair production of electron and positron closed loops? What in the
Maxwell Equations trips up that wave front into closed loops.
And in pair annihilation when a electron collides with positron of two
closed loops, what in the Maxwell Equations allows those closed loops
to become opened up and go speeding off at the speed of light
in a wave of this structure:

E-
M+ M-
E+

--

Google's archives are top-heavy in hate-spew from search-engine-
bombing. Only Drexel's Math Forum has done a excellent, simple and
fair archiving of AP posts for the past 15 years as seen here:

http://mathforum.org/kb/profile.jspa?userID=499986

Archimedes Plutonium
http://www.iw.net/~a_plutonium
whole entire Universe is just one big atom
where dots of the electron-dot-cloud are galaxies

Date Subject Author
2/13/13 plutonium.archimedes@gmail.com
2/13/13 capuc