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Re: Finding an easy substitution for a complicated function
Posted:
Mar 12, 2013 6:51 AM


On 06.03.13 09:32, Asma wrote:
> I have a very tedious function (including arctan, arcsin, sqrt etc) having a number of controlling parameters. > When I plot this function, I get a simple exponential looking curve.
If your function is exactly of a simple form, the SIMPLIFY command from the symbolic toolbox may be able to find it.
HTH,
Christopher



