Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: deriving Jupiter's 15 pulsar pulses per 10 hours Chapt16.15 Gravity
Cells #1485 ATOM TOTALITY 5th ed

Replies: 16   Last Post: Apr 10, 2013 6:26 PM

 Messages: [ Previous | Next ]
 plutonium.archimedes@gmail.com Posts: 18,572 Registered: 3/31/08
deriving Jupiter's 15 pulsar pulses per 10 hours Chapt16.15 Gravity
Cells #1485 ATOM TOTALITY 5th ed

Posted: Apr 10, 2013 4:47 PM

On Apr 6, 12:33 am, Archimedes Plutonium
<plutonium.archime...@gmail.com> wrote in #1473:
> This math is bothering me, so let me try to nail it.
>
> We have the problem of the force of gravity. There is no problem if
> the Sun had 0 speed, but the Sun is 220 km/sec, far faster than any of
> its planets and so there is a huge problem.
>
> To solve the problem, we need the force of gravity to be EM-gravity
> with Space itself having been formed by gravity and then, that newly
> formed space to have a spin.
>
> So, now, how to work out the spin.
>
> We go to the planet most close to the Sun, which is Mercury.
>
> Now there would be no problem if the planets had their orbital speeds
> plus tacked on a 220km/sec.
>
> Thus, Mercury would be alright if its true speed were 267km/sec rather
> than 47km/sec. (sic)
>
> So that if Mercury and the Sun were moving in a straight line and at a
> distance apart of 0.4AU in Euclidean Space that they would be the
> orbits we know of today. However, Mercury is not moving at a 267km/sec
> speed in Space.
>
> So, we have elliptical geometry Space and this space has a spin. So
> what measure of a spin of Space so that 47km/sec is required to go
> around the Sun moving at 220km/sec. Now one complete revolution of
> Mercury is 88 days.
>
> So how much of a spin is required of this Elliptical geometry Space to
> carry the Mercury planet around at 47km/sec, around the Sun moving at
> 220km/sec.
>
> So, now, if the Space was spinning at 88 days for one complete
> revolution, then the planet Mercury need go 0km/sec and it would be
> making 1 complete orbit. But Mercury is not going at 0 km/sec but
> rather at 47km/sec. So, I think the ratio I need to build on is this
> ratio:
>
> 88     267
> X       220
>
> And now, cross multiplying I get 88x220 = 267X
>
> And solving for X, I get 19360/267 = 72.5.
>
> So the rotation for one complete revolution of the Solar gravity-cell
> is that of 72.5 days.
>
> So when I did this last night and came up with 70 days, I was more
> correct than in the next day thinking it had to be 110 days.
>
> Now the other worry was how would a spinning of the Solar gravity cell
> fix the revolution of Earth at 29km/sec or the revolution of Jupiter
> at 13 km/sec?
> It is solid body rotation of the Solar Gravity Cell, but it takes 1
> complete turn of 72.5 days to fix Mercury at 47km/sec and 88 days. It
> takes 3 or more complete turns of the Solar Gravity Cell to render
> Venus and 5 or more complete turns to render Earth of its 29km and 1
> year full revolution and takes about  60 or more Cell complete spins
> to render Jupiter of its 13km/sec and its 11.8 years.
>
> Now the spinning of the Solar Gravity Cell is solid body rotation, but
> the orbits of the planets is not solid body rotation. The orbits of
> the planets are "aided or helped out along their path, by the spinning
> of the Sun's gravity cell."
>
> So if Michael Wright were to be so kind as to build a Antikythera
> Mechanism that is heliocentric and which has the Sun depicted as a
> linear forward motion of 220km/sec, then to counterbalance that motion
> a gear wheel has to be engineered so that
> it makes the entire Solar Ecliptic revolve one complete circuit in
> 72.5 days.
>
> Hopefully I got it correct now. On issues so complex as astro body
> motion, we often mistake one side for the other side, we get 70 and
> then think it wrong and get 110, and finally we go back to the 70
> (72.5).
>
> Now Gravity Cells would solve many other problems and questions in
> astronomy. Earlier today I wrote that pulsars are likely to be two
> nearby gravity cells pushing on one another as a Faraday law and
> producing a pulsed radio signal.
>
> Gravity Cells also solve the question of redshift of stars and
> galaxies, because of the high degree of bent space, that light
> traveling through the bent space is shifted by diffraction or
> refraction into the red wavelengths. So that the Shapley concentrate
> of galaxies may actually be a close by neighbor of the Milky Way.
>
> Gravity Cells also allow us to unravel the mystery of the morphology
> and evolution of galaxies, that they are all ball shaped once we
> include the gravity cell with the galactic plane of the galaxy.
>
> And Gravity Cells solves the question of where galaxies are locating
> in the mapping of the Universe.
> And I am delighted to say that the galaxies are spaced very evenly and
> uniformly, much like a fruit tree orchard of evenly spaced trees in
> rows.
>

So now, the gravity cell of the Sun spins around its axis and augments
the orbit of Mercury so that it can orbit with 47km/sec whilst the Sun
is moving in space at 220km/sec.

So now I am wanting to get 15 Jupiter pulsar pulses in 10 hours time
rotation of Jupiter from this 2002 NASA report:

-- quoting from ?http://science.nasa.gov/science-news/science-at-nasa/2002/07mar_jupit...
"The pulses are coming from the north pole of Jupiter," says Randy
of the team that made the discovery using NASA's orbiting Chandra X-
ray Observatory. ?Above: Every 45 minutes an x-ray source blinks near
Jupiter's north ?magnetic pole. This animation, based on data from the
Chandra X-ray ?Observatory, shows the hot spot pulsing 15 times during
one complete ?10-hour rotation of the giant planet. ?-- end quote --

I want to apply that Solar gravity cell of 72.5 days of rotation per
every single complete revolution.

--

Approximately 90 percent of AP's posts are missing in the Google
newsgroups author search starting May 2012.

Only Drexel's Math Forum has done a excellent, simple and fair author-
archiving of AP sci.math posts since May 2012 as seen here:

http://mathforum.org/kb/profile.jspa?userID=499986

Archimedes Plutonium
http://www.iw.net/~a_plutonium
whole entire Universe is just one big atom
where dots of the electron-dot-cloud are galaxies

Date Subject Author
4/10/13 plutonium.archimedes@gmail.com
4/10/13 bacle
4/10/13 bacle
4/10/13 bacle
4/10/13 bacle
4/10/13 bacle
4/10/13 bacle
4/10/13 bacle
4/10/13 bacle
4/10/13 bacle
4/10/13 bacle
4/10/13 bacle
4/10/13 plutonium.archimedes@gmail.com
4/10/13 bacle
4/10/13 bacle
4/10/13 bacle
4/10/13 bacle