On Thursday, June 27, 2013 10:48:15 PM UTC+1, quasi wrote: > pepstein5 wrote: > > > > >Let gamma be a simple closed curve in R^2. Is the bounded > > >component of the complement of gamma always Lebesgue > > >measurable? > > > > The components of the complement gamma are open, hence are > > measurable. > > > > quasi
I mistakenly assumed this problem was difficult so I didn't spend enough time thinking about it for myself.