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Topic: Some where equidistant
Replies: 5   Last Post: Jul 16, 2013 4:29 AM

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David C. Ullrich

Posts: 3,555
Registered: 12/13/04
Re: Some where equidistant
Posted: Jul 13, 2013 12:10 PM
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On Fri, 12 Jul 2013 21:05:15 -0700, William Elliot <>

>Let (S,d) be a compact connected metric space and
>f:S -> S a homeomorphism. How would one show
>there's some distinct x,y with d(f(x),f(y)) = d(x,y)?

You still haven't given a correct statement of the
problem! One of the counterexamples quasi
mentioned is a counterexample to this version
as well.

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