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Topic:
Some where equidistant
Replies:
5
Last Post:
Jul 16, 2013 4:29 AM




Re: Some where equidistant
Posted:
Jul 13, 2013 12:10 PM


On Fri, 12 Jul 2013 21:05:15 0700, William Elliot <marsh@panix.com> wrote:
>Let (S,d) be a compact connected metric space and >f:S > S a homeomorphism. How would one show >there's some distinct x,y with d(f(x),f(y)) = d(x,y)?
You still haven't given a correct statement of the problem! One of the counterexamples quasi mentioned is a counterexample to this version as well.



