
Math professors of Univ Michigan endorsing Kepler Packing proof to arxiv
Posted:
Jun 17, 2014 2:55 PM


Alright, the reason Kepler Packing Problem KPP, was never proven in mathematics, is not because it is a difficult proof, but because there are two definitions involved that are very much cloudy, foggy and illdefined. When you have one definition illdefined is enough to prevent there ever being a math proof, but in the case of KPP, there are two illdefined definitions: (1) finite versus infinity with a borderline between them (2) density definition
If we define density to be surface area contact by equal spheres, then the maximum kissing points is 12 and there is a theorem in mathematics that proves 12 is maximum. The theorem is called the Euler regular polyhedra formula of VE+F = 2. In this definition of density, the surface area is the "Container involved". So if Kepler had stated his KPP as kissing point density, he probably could not have proven his own conjecture, because the Euler formula was not available, although Kepler could have reasoned that it is impossible for 13 unit spheres to surround and kiss a central sphere due to exhaustion of angles.
KEPLER PACKING PROVED:
Now to make the proof that 12 is the maximum kissing points allowed in sphere packing of Kepler and that no central sphere can have 13 kissing points uses the Euler regularpolyhedra formula of Vertices  Edges + Faces = 2. So that if a central sphere has surrounding it 13 spheres with kissing points violates this Euler formula.
But what I have neglected to mention over the course of the commentary on Kepler Packing is that the proof of the Moebius theorem used in 5 Color Mapping is proven also by the Euler formula. The Moebius theorem, if you remember states that the maximum allowed mutual adjacencies of countries is 4, since the fourth country surrounds at least one of the other three and encloses it to any further adjacency.
So here is a fine example of where a theorem Euler regularpolyhedra formula is crucial to Mapping and crucial to Packing. So why would the Euler formula be so versatile? The answer is simple and easy for each regularpolyhedra fits inside a sphere and the regular polyhedra is all about allowable angles for faces. A 13 kissing points of a sphere is not allowed by that formula of VE+F=2, and that same formula does not allow 5 mutual adjacencies in a Moebius theorem.
The proof that a unit sphere has at most 12 surrounding unit spheres of kissing points and never 13 kissing points comes from that Euler formula. We model the dodecahedron where its 12 faces become the vertices of 12 kissing points on the sphere surface.
Perhaps an even easier proof is to realize that the 12 surrounding unit spheres are all in turn 6 spheres with 3 left and 3 right, or 3 up and 3 down but all the 12 spheres in turn are a ring of 6 around the central sphere. Now if 13 can be kissing points means that 7 would be in that ring instead of 6. And we know from plane geometry that a regular heptagon is not constructible with compass and straightedge but that a regular hexagon is constructible.
128.57.. degrees internal angle for heptagon
120 degrees internal angle for hexagon
So we have 8.57.. degrees too much to support a 7th unit sphere kissing point.
QED
Now in modern times there is a silly objection to the above proof in that some coneheads of logic think that a higher dimension that kissing points start to vary is a objection. But such coneheads have never proven to math that a dimension higher than 3rd ever or even exists. In this textbook of "Correcting Math" it is proven that no 4th or higher dimension exists, but rubbish make belief. The proof that 3rd is the last dimension is proven that a 4th dimension causes the planes of 2nd dimension to be bent and have a 90 degree twist in the plane. So for anyone to object to a proof of kissing points because of higher dimensions is like someone objecting to something in "real life" because they staunchly believe in ghosts, witches and the fire breathing dragons.
However, if you do not define density as surface contact intersection, then density is defined as to Space as a container. And since Kepler and all his later day followers never defined "infinity" with precision, that there would never be a proof of KPP, so long as infinity is illdefined.
If you take the unit Tractrix area and unit circle area and follow them out to Floorpi*10^603, you discover there is a crossover in amount of area. That the area of circle is always greater except when it reaches floorpi*10^603 and then the tractrix area becomes momentarily greater than the circle. In that crossover is the Infinity borderline.
So, to prove KPP, with a precision definition of what it means to be finite and infinite, that the 1*10^603 by 1*10^603 by 1*10^603 is a container, and the KPP question becomes, is the Hexagonal Closed Pack the most dense packing of that container (and all the smaller sized cube containers)?
Well, the answer surprises most people, in that a Hybrid form of Hexagonal Closed Pack is more dense than the pure Hexagonal Closed Pack, because near the walls, edges and corners, we can rearrange some of the Hexagonal Closed Pack to fit more unit spheres and make a denser packing.
I wrote awhile ago:
Alright, well, we could never have asked Kepler to define precisely infinity with a borderline, for he would never have had the ability to know the Tractrix and Circle area are equal at Floorpi*10^603 and thus infinity border is 1*10^603. And then Kepler could have said for his Conjecture, that the hexagonal closed pack is the most dense packing ***for the majority of the packing*** of equal unit spheres in a container that is 1*10^603 by 1*10^603 by 1*10^603. Then, mathematicians would have looked to see if there was a more dense packing. And it turns out, that there is a more dense packing as we manipulate the last plane and last edge and last corners to fit more spheres in an otherwise pure Hexagonal Closed Pack. The most dense packing depends on the size of the container.
Now, if density is defined as how many other spheres can be packed onto a single sphere the kissing points, then in that density definition, the proof of Kepler Packing is a one paragraph proof that 12 kissing points is maximum. The surface of a single sphere would be considered "the container".
But Kepler had in mind something different for density as a container. Now if one does not define finite with infinity properly as a borderline, then empty space that is infinite empty space is meaningless, because the Space cannot tell you whether you are in "finite space" or infinite space. In total empty space, means there is only finite space, because no border was reached to say, now we are in infinite space.
So if we define Infinite Space as a borderline that is crossed and that forms a container such as the 1*10^603 by 1*10^603 by 1*10^603 cube.
Now we can get an induction notion of this container of Space by smaller cubes such as 10 by 10 by 10 or the 100 by 100 by 100 cube and ask whether the most dense packing is the same as we go higher in cubes?
It turns out that a Hybrid form of Hexagonal Closed Pack is the most dense packing possible for it allows more unit spheres into a container than the pure Hexagonal Closed Pack.
In the below old post of mine, I illustrate this Hybrid Hexagonal Closed Pack.
I wrote awhile ago:
Alright, in my prior post, the illustration was messed up in format, so here I hope to have cleared up view of the illustration.
Now I think that the maximum hybrid of hexagonal closed pack is going to add spheres in the corners and edges, but I fail to see or recollect in my memory how an entire plane of new spheres can be added to a stock of hexagonal closed pack. If the body of the packing is hexagonal closed pack, I fail to see how an entire plane can be added in a hybrid. I think I came to that conclusion many years back when I first did these hybrid packings, but want to make sure of that memory.
Here is the illustration:
OOOO ?OOOOO
when the headroom of the ceiling face is large enough to scoot ?that upper layer to the rightward side then we can add a new sphere ?shown by the X
XOOOO ?OOOOO
And if the upper layer is full then we do the scooting on the second ?to top ?layer as such: OOOOO ? XOOOO And here is the illustration of Oblong Hex when the square or cube has ?a 0.99 after the integer
O 9 ?_O 8 ?O 7 ?_O 6 ?O 5 ?_O 4
The underline indicates a distance of 0.99 to the wall. Those ?are either spheres in 3D or circles in 2D and they are numbered ?for easy reference. In the Oblong technique we scoot 5 downwards leaving a gap ?large enough to pack a new sphere or circle. We leave 6 undisturbed ?but move 7 downwards leaving a gap which we add a new circle or ?sphere. And we do that entire face of both the length face and width ?face, depending on whether we are in 3D or 2D.
Newsgroups: sci.math, sci.physics, sci.logic From: Archimedes Plutonium <plutonium.archime...@gmail.com> Date: Mon, 18 Jul 2011 09:16:34 0700 (PDT) Local: Mon, Jul 18 2011 11:16 am Subject: Chapt2 seeing if Kepler Packing can match the Omega function for Infinity #xxx Correcting Math 3rd ed
Just minutes ago I posted a reply to Carl for his finding the 10^603 of the 1.000..01 form in the Omega function (Lambert W function) What I want to see is whether Kepler style Packing is another form of ?the Omega function, perhaps a hybrid of a trigonometric function along ?with the logarithmic omega function. See whether the most dense packing uniquely occurs at 10^603. So I start a table below using Unit Diameter and where the trough ?height is 0.133974 from that of ?0.8660254 sq size, max pack, max rows, height of max pack, #circles, circl/ ?square density 1x1 pole 1 ?1 1 0.7853 2x2 pole 2 ?2 4 0.7853 3x3 pole 3 ?3 9 0.7853 4x4 pole 4 4 ?16 5x5 pole 5 5 ?25 6x6 pole 6 6 ?36 7x7 pole 7 7 ?49 8x8 hex 9 7.9282 ?68 0.8344 9x9 oblonghex 10 8.7942 + 0.1339 86 0.8338 10x10 oblonghex 11 9.66025 + 0.1339 105 11x11 oblonghex 12 10.5262 + 0.1399 12x12 oblonghex 13 11.3923 + 0.1399 13x13 oblonghex 14 12.2583 + 0.1399 14x14 hex 16 13.99 15x15 oblonghex 17 14.8564 +0.1399 16x16 Tables are good for seeing general trends. If I can see a trend with ?the small ?numbers, I could find out what happens at 10^603 The Logic would be that at Infinity, there is a maximum of empty space ?or a ?maximum of occupied space. One or the other, making Infinity special. Archimedes Plutonium ?http://www.iw.net/~a_plutonium ?whole entire Universe is just one big atom ?where dots of the electrondotcloud are galaxies
 end of old 2011 post of mine on the depression number in Kepler Packing 

Recently I reopened the old newsgroup PAU of 1990s and there one can read my recent posts without the hassle of frontpagehogs since they crowd out everyone else reading "mobile" instead of "desktop". Many posters in sci.physics and sci.math are not doing science but seeing whether they can dominate the front page of the newsgroup, and PAU is free of hogs, mockers and hatemongers.
https://groups.google.com/forum/?hl=en#!forum/plutoniumatomuniverse Archimedes Plutonium

