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Topic:
question on when definte integral evaluates, but indefinite does not.
Replies:
2
Last Post:
Nov 14, 2017 5:21 AM




question on when definte integral evaluates, but indefinite does not.
Posted:
Sep 20, 2017 11:41 PM


How is it possible that CAS can evaluate an integral symbolically when it is definite, but not able to when it is indefinite? This is all symbolic integration, not numerical ofcourse.
Here is an example:
Assuming[Im[p] != 0, Integrate[1/(E^z^2*(p  z)),{z, Infinity, Infinity}]]
(Pi*Erfi[p]  Log[(1/p)]  Log[p])/E^p^2
But
Assuming[Im[p] != 0, Integrate[1/(E^z^2*(p  z)), z]]
Returns unevaluated.
I tried the above on Maple, but could not make it give same result, it return unevaluated for both cases.
Mathematica 11.2
Nasser



