The Math Forum



Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.


Math Forum » Discussions » sci.math.* » sci.math.symbolic

Topic: question on when definte integral evaluates, but indefinite does not.
Replies: 1   Last Post: Sep 21, 2017 10:25 AM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
Nasser Abbasi

Posts: 6,654
Registered: 2/7/05
question on when definte integral evaluates, but indefinite does not.
Posted: Sep 20, 2017 11:41 PM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply


How is it possible that CAS can evaluate an integral
symbolically when it is definite, but not able to
when it is indefinite? This is all symbolic integration,
not numerical ofcourse.

Here is an example:

Assuming[Im[p] != 0, Integrate[1/(E^z^2*(p - z)),{z, -Infinity, Infinity}]]

(Pi*Erfi[p] - Log[-(1/p)] - Log[p])/E^p^2

But

Assuming[Im[p] != 0, Integrate[1/(E^z^2*(p - z)), z]]

Returns unevaluated.

I tried the above on Maple, but could not make it give same result,
it return unevaluated for both cases.

Mathematica 11.2

--Nasser



Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2017. All Rights Reserved.